center to center distance between objects: Need advise
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I am trying to calculate center to center distance between lines, i.e., between intersection points. I am working on this image

I want to achieve this

However, following steps I have assumed like
- detect centerlines in the image.
- detect intersection points.
- calculate horizantal distances between intersecting points.
- calculate vertical distances between intersecting points.
I am a bit confused about functions to be applied here. If anyone can advice which fucntions will be helpful to be to achieve above outcome OR if there is some better methodlogy to achieve above shared outcome. Kindly advise.
2 Comments
Alberto Cuadra Lara
on 30 Apr 2022
Edited: Alberto Cuadra Lara
on 30 Apr 2022
Hi Abdul,
I haven't done any image processing for a long time, but maybe these comments can help.
- Remove image noise (imguidedfilter).
- Black and white conversion (rgb2gray).
- Convert to binary (imbinarize).
- Remove all elements smaller than a certain number of pixels (bwareaopen).
- Obtain the center of each line (regionprops).
If you know the pixel relation you can obtain also the values in micrometer, for example.
Best,
Alberto
Abdul Hannan Qureshi
on 30 Apr 2022
Accepted Answer
More Answers (1)
Image Analyst
on 30 Apr 2022
0 votes
What I'd do is what I actually do in a very similar situation, though I'm looking for 5 points on the perimeter not 5. Here is the algorithm I think you can use
- binarize the image to find dark rectangles mask = imbinarize();
- call mask = bwareafilt(mask, [smallest, largest]) to get rid of small blobs and the super large one touching the border and get ONLY the valid squares.
- call imfill(mask, 'holes');
- Find centroid with props = regionprops(mask, 'Centroid', 'Image')
- Loop over all blobs and for each blob, props(k).Image, find boundaries with bwtraceboundary. Start on the left middle edge so you have a known starting point.
- Find distance of all boundary points to that blob's centroid and plot them. distances = sqrt((xCentroid-x)^2+(yCentroid2-y)^2)
- Find peaks with findpeaks(distances, .....). Specify the MinPeakDistance as half the approximate width of the square. If there are more than 4 peaks found, take the 4 with the highest prominence value. This gives you the index of the corners in the boundary coordinates. You'll have 1 is the upper left, 2 = upper right, 3 = lower right, and 4 = lower left.
- Compute distances like d12 = sqrt((x2-x1)^2+(y2-y1)^2), and similar for d23, d34, and d41. Stored the distances for each blob.
If you can't code it up from the pseudocode I've given so far, then let me know and I'll finish it.
1 Comment
Abdul Hannan Qureshi
on 30 Apr 2022
Edited: Abdul Hannan Qureshi
on 6 May 2022
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