Divide a column of a datafile through a constant value

I have a large number of datafiles (.txt file) and I need to divide one of the columns to a constant number. What is the short way to do it.

3 Comments

Import your data (preferably in a table/double matrix) and then perform the operation.
How large is your data exactly?
Around 70 files having 40 columns each.
a = textread('den_T50.txt');
a1 = a(:,1)/0.15;
save ('den_T50.txt','-ascii')
type('Nden_T50.txt')
I have tried this way for a single file. Is there can be any short method for saving a large number of files other than this?
And further, the problem is on saving the new data file (according to above code) it's just appending the modified data column into the previous data. Whereas I want to replace the previous column with the new calculated one.

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Answers (1)

txtFiles = dir('*.txt') ; % you are in the folder of text files
N = length(txtFiles) ; % total files
% loop for each file
for i = 1:N
txtFile = txtFiles(i).name ;
T = readtable(txtFile) ; % also have a look on load, importdata
T.(1) = T.(1)/100 ; % divide first column by 100
end

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Asked:

on 23 May 2022

Commented:

on 23 May 2022

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