# I want to find unique value(s) based on a given conditions

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Tulkkas on 2 Aug 2022
Commented: Jeffrey Clark on 3 Aug 2022
I have 2 arrays a and b:
a = [datetime(2020,1,2), datetime(2020,1,5), datetime(2020,1,6), datetime(2020,2,3), datetime(2020,2,8),datetime(2020,3,4),datetime(2020,3,10),datetime(2020,4,11)]'
b = {'2020_01';'2020_01';'2020_01';'2020_02';'2020_02';'2020_03';'2020_03';'2020_04'}
I want to find the indices of unique element of b and if there are ties, choose the most recent based on a.
in the case, the indices that I would like to identify are the following:
indices = [0,0,1,0,1,0,1,1]'
I can of course do it with a loop but I am interested in a vectorize solution using unique, which I was not able to figure out so far.

Jeffrey Clark on 3 Aug 2022
@Tulkkas, this should do it (I added a randomize of your sorted data since first, if it would always be sorted skip as indicated):
a = [datetime(2020,1,2), datetime(2020,1,5), datetime(2020,1,6), datetime(2020,2,3) ...
, datetime(2020,2,8),datetime(2020,3,4),datetime(2020,3,10),datetime(2020,4,11)]';
b = {'2020_01';'2020_01';'2020_01';'2020_02';'2020_02';'2020_03';'2020_03';'2020_04'};
% setup data assuming future datasets won't be sorted already
L = length(a);
I = randperm(L);
a = a(I);
b = b(I);
% sort datasets
[a,i] = sort(a);
b = b(i);
% extract unique data
[bu,ui] = unique(b,'last');
au = a(ui);
Tulkkas on 3 Aug 2022
Great that does the trick, thx!
Jeffrey Clark on 3 Aug 2022
@Tulkkas, or if you want the last two lines (the actual work) can be:
indices = [string(b(1:end-1))~=string(b(2:end));false];
indices(end) = indices(end-1);

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