Conversion of linear equations to form Ax=b

4 views (last 30 days)
Hello everyone,
I have the following equations:
syms t u v w x y z
intersection_a = -t + w + x == 100;
intersection_b = t - u == 100;
intersection_c = v + w - y - z == 0;
intersection_d = u + v == 40;
I can convert it to form of Ax=b using equationsToMatrix(). But my question is if I have t = 100 and w+x+y = 100, then does the equation change? Do I need to put t = 100 etc in these equations? If I will, then there will be no t in equations. How I will be able to write then it in form of Ax= b where x = [t u v w x y z] '?
Thanks in advance.

Accepted Answer

Sam Chak
Sam Chak on 15 Sep 2022
You have only 4 equations, but there are 6 unknowns. So, the linear system is clearly rank-deficient.
syms t u v w x y z
t = 100;
intersections = [-t + w + x == 100, ...
t - u == 100, ...
v + w - y - z == 0, ...
u + v == 40];
vars = [u, v, w, x, y, z];
[A, b] = equationsToMatrix(intersections, vars)
A = 
b = 
x = linsolve(A, b)
Warning: Solution is not unique because the system is rank-deficient.
x = 
  6 Comments
Torsten
Torsten on 15 Sep 2022
If it has to be satisfied, it has to be included. Why do you ask for this specific equation ? Is it different from the others ?

Sign in to comment.

More Answers (0)

Categories

Find more on Get Started with Symbolic Math Toolbox in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!