How to create surface plot from vertical lines?

Hello, I'd like to ask few questions related to creating 3D surfaces.

I have created wireframe figure(red) of propeller blade as below, but I don't know how to create surface.

I created (z-direction) wireframes by connecting points at same index("lv" in first for-loop) in all sections. For example, let's say there are 3 sections A, B and C, and each section carries same number of points. Those points are (x, y, z) coordinates, and each section is 2D matrix with same size.

Then, I connect 1st point of A with 1st point of B, and 1st point of C, using plot3, and so on.

I believe, I can create single surface by using 2-vertical(Z-direction) lines, and the very bottom section and top section. I tried to implement it by myself, but the result shown in blue wasn't satisfying.

Below is the code I used to create the figure above.

% ----------------- creates wireframe here --------------------
lv_dim = [size(coordinates_list)];
rows = lv_dim(1);  % number of points in each section
depth = lv_dim(3); % number of all sections
% coordinates_list: 3D matrix that contains x-y-z coordinates of each
% section

for lv = 1:rows
    x_line = reshape([coordinates_list(lv, 1, :)], [1, depth]); % X coordinate of lv-th point, from all sections in coordinates_list
    y_line = reshape([coordinates_list(lv, 2, :)], [1, depth]); % Y coordinate of lv-th point, from all sections in coordinates_list
    z_line = reshape([coordinates_list(lv, 3, :)], [1, depth]); % Z coordinate of lv-th point, from all sections in coordinates_list
    
    wire_line(lv) = plot3(app.UIAxes, x_line, y_line, z_line, 'r-'); % Create lv-th wire frame at app.UIAxes,(shown above).
    axis(app.UIAxes,'equal');
    hold(app.UIAxes,'on');
end


% ------------------ creates surface here ------------------------
for lv = 2:rows
    % left vertical(Z-direction) boundary
    x_line_l = reshape([coordinates_list(lv-1, 1, :)], [1, depth]); % reshape matrix of X-coordinates from left boundary into colum vector
    y_line_l = reshape([coordinates_list(lv-1, 2, :)], [1, depth]); % reshape matrix of Y-coordinates from left boundary into colum vector
    z_line_l = reshape([coordinates_list(lv-1, 3, :)], [1, depth]); % reshape matrix of Z-coordinates from left boundary into colum vector
    
    % right vertical(Z-direction) boundary
    x_line_r = reshape([coordinates_list(lv, 1, :)], [1, depth]); % reshape matrix of X-coordinates from right boundary into colum vector
    y_line_r = reshape([coordinates_list(lv, 2, :)], [1, depth]); % reshape matrix of Y-coordinates from right boundary into colum vector
    z_line_r = reshape([coordinates_list(lv, 3, :)], [1, depth]); % reshape matrix of Z-coordinates from right boundary into colum vector
    
    % concatenate colum vectors per each axis(x, y, z) and-
    % -transpose.
    surf_line(lv) = surf(app.UIAxes,[[x_line_l x_line_r]', [y_line_l y_line_r]', [z_line_l z_line_r]']);
    axis(app.UIAxes,'equal');
    hold(app.UIAxes,'on');
end

I sincerely appreciate you for your attention, and I'd be happy to hear and implement your suggestions.

Answer 1

[Star Strider]

If you can change that to a series of cross-sections of the propeller blade at various points along its length, the approach in how to convert 2D graph to 3D? could work.

[sea_centipede]

Thank you for your reply!

I'll try it out!!

[Star Strider]

My pleasure!

[sea_centipede]

I've implemented your suggestion, it worked like a charm.

Again, Thank you for your opinion and sorry for being late!!

[Star Strider]

My pleasure!

If my Answer helped you solve your problem, please Accept it!

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