Matrices layering - two matrix layering

How I layer 2 matrices on top of each other? assume we have a A = 2x2 matri,x and B = 2 x2 matrix
A = [1 1;1 1] ,
B = [0 0 ; 0 0 ] ,
A(22) = 1 is the "start of layring":
L1 = first layer result is [1 0; 0 0 ] , means = > [B(11)+A(22) B(12); (B21) B(22)]
L2 = 2nd layer result is [ 2 1 ; 0 0 ] , means = > [L1(11)+A(21) L1(12)+A(22) ; L1(21) L1(22)]
L3 = 3d layer result is [3 1 ;1 1 ], means = > [L2(11)+A(12) L2(12) ; L2(21)+A(22) L2(22)]
L4 = and the fianl layer is [4 2 ; 2 1 , means = > [L3(11)+A(11) L3(12)+A(12) ; L3(21)+A(21) L3(22)+A(22)]

3 Comments

You have done that already, you just need to use the proper indexing syntax
A = [1 1;1 1];
B = [0 0;0 0];
L1 = [B(1,1)+A(2,2) B(1,2); B(2,1) B(2,2)]
L1 = 2×2
1 0 0 0
L2 = [L1(1,1)+A(2,1) L1(1,2)+A(2,2) ; L1(2,1) L1(2,2)]
L2 = 2×2
2 1 0 0
L3 = [L2(1,1)+A(1,2) L2(1,2) ; L2(2,1)+A(2,2) L2(2,2)]
L3 = 2×2
3 1 1 0
L4 = [L3(1,1)+A(1,1) L3(1,2)+A(1,2) ; L3(2,1)+A(2,1) L3(2,2)+A(2,2)]
L4 = 2×2
4 2 2 1
Thank you , but I know I have an answer for 2x2, this is just an example, the problem in large scale. How you do a 1920x1080 matrix if element (750,750) need to be the start of layring on (1,1) ?
If I am understanding correct, you want
L1 = [B(750,750)+A(751,751) B(750,751); B(751,750) B(751,751)]
%similarly for L2, L3 and L4 as well
for starting point (750,750)

Sign in to comment.

Answers (0)

Categories

Find more on Deep Learning Toolbox in Help Center and File Exchange

Asked:

on 21 Mar 2023

Commented:

on 22 Mar 2023

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!