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Youssef Khmou
on 29 Mar 2015

the following answer is an alternative approach without using 'getdigits' function :

function [C,y]=sum3(x)

h=int2str(x);

N=length(h);

for n=1:N

C(n)=str2num(h(n));

end

y=sum(C);

Stephen Cobeldick
on 29 Mar 2015

Edited: Stephen Cobeldick
on 30 Mar 2015

Although an answer has already been accepted, that answer shows very poor use of MATLAB by solving this using nested loops and multiple calls to the rather slow str2num within each loop iteration. A much simpler, neater and faster solution would be to vectorize the whole code and use basic MATLAB practices, something like this:

>> A = [123,4,567890];

>> B = int2str(A(:))-48;

>> B(B<0) = 0

B =

0 0 0 1 2 3

0 0 0 0 0 4

5 6 7 8 9 0

>> sum(B,2)

ans =

6

4

35

This will work for vectors of any length (i.e. A can have any number of values in it), it will be faster that a loop-based solution (especially if A has more values in it), and it uses fewer lines of code too!

Stephen Cobeldick
on 30 Mar 2015

MATLAB is a high-level language, which means that it has faster and neater ways of solving basic arithmetic than using loops: loops are the second choice in MATLAB, code vectorization is the preferred choice! Loops are what are needed in low-level languages like C, etc.

The concept is very simple: many basic arithmetic operations and MATLAB functions operate on complete matrices at once, without requiring any loops. This is called vectorization, and it is much faster, neater code, and it looks more like the mathematics as it would be written.

If you want to learn MATLAB, then do not learn bad programming habits first: instead learn the recommended practices and your code will be much improved.

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Youssef Khmou
on 30 Mar 2015

Edited: Youssef Khmou
on 30 Mar 2015

This function works for a vector of length n, with second logical output according to the description :

function [Logical,y]=sumn(x)

N=length(x);

for iter=1:N

h=int2str(x(iter));

NN=length(h);

C=zeros(1,NN);

for n=1:NN

C(n)=str2num(h(n));

end

S=sum(C);

y(iter)=S;

if mod(S,2)==0

Logical(iter)=true;

else

Logical(iter)=false;

end

end

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