How to break a single horizontal line in the legend of a Matlab plot into two horizontal lines?

I have a legend as follows:` lg=legend([pl_1, pl_6, pl_s_1, pl_s_6, pl_s_3, pl_s_7], 'disc (impuls)', 'disc (step)', 'stoch1 (impuls)', 'stoch1 (step)', 'stoch (impuls)', 'stoch (step)', 'interpreter','latex','fontsize',34,'orientation','horizontal','position',[0.12 0.04 0.8 0.034]); The legend with six items is too long, and I've attempted to split it into two lines, with the first four items in the first line and the remaining two in the second line. However, despite trying various approaches, the legend remains on a single line without any breaks. I wonder how to resolve this issue.

For additional details, I've listed the options I've attempted below:

#Case 1

legend([pl_1, pl_6, pl_s_1, pl_s_6, pl_s_3, pl_s_7], ... 'disc (impuls)', 'disc (step)', 'stoch (impuls)', 'stoch (step)', ... 'stoch1 (impuls)\newline', 'stoch (step)', ... 'interpreter', 'latex', 'fontsize', 34, 'orientation', 'horizontal', ... 'position', [0.12 0.04 0.8 0.034]);

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#Case 2

% Create the legend

legend([pl_1, pl_6], {'disc (impuls)', 'disc (step)', ... 'stoch (impuls)', 'stoch (step)', 'stoch1 (impuls)', 'stoch (step)'}, ... 'interpreter', 'latex', 'fontsize', 34, 'orientation', 'horizontal', ... 'position', [0.12 0.04 0.8 0.034]);

% Modify the legend to split the line

lgd = legend('Location', 'southoutside'); lgd.String{5} = 'stoch1 (impuls)'; lgd.String{6} = 'stoch (step)';

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#Case 3

% Create a legend using text objects

lgd_pos = [0.12, 0.04, 0.8, 0.034];

lgd_text = {'disc (impuls)', 'disc (step)', 'stoch (impuls)', 'stoch (step)'};

lgd_text{end+1} = 'stoch1 (impuls)';

lgd_text{end+1} = 'stoch (step)';

lgd_handles = zeros(1, numel(lgd_text));

for i = 1:numel(lgd_text)

lgd_handles(i) = text(lgd_pos(1) + (i - 1) * lgd_pos(3) / numel(lgd_text), ... lgd_pos(2), lgd_text{i}, 'Interpreter', 'latex', 'FontSize', 34, 'HorizontalAlignment', 'center');

end

% Remove the default legend

legend off;

% Set the legend position manually

legend(lgd_handles, lgd_text, 'Interpreter', 'latex', 'FontSize', 34, 'Orientation', 'horizontal', 'Position', lgd_pos);

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#Case 4

% Create the legend with LaTeX markup legend([pl_1, pl_6], {'disc (impuls)', 'disc (step)', 'stoch (impuls)', 'stoch (step)', 'stoch1 (impuls) \\newline stoch (step)'}, 'interpreter', 'latex', 'fontsize', 34, 'orientation', 'horizontal', 'position', [0.12 0.04 0.8 0.034]);

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#Case 5

% Create the first part of the legend

legend([pl_1, pl_6, pl_s_1, pl_s_6, pl_s_3, pl_s_7], {'disc (impuls)', 'disc (step)', ... 'stoch (impuls)', 'stoch (step)'}, 'interpreter', 'latex', 'fontsize', 34, 'orientation', 'horizontal',... 'position', [0.12 0.04 0.8 0.034]);

% Create the second part of the legend below the first one

lgd_text = {'stoch1 (impuls)', 'stoch (step)'}; lgd_pos = get(legend, 'Position');

% Get the position of the first legend

lgd_pos(2) = lgd_pos(2) - 0.06;

% Adjust the vertical position

legend(lgd_text, 'interpreter', 'latex', 'fontsize', 34, 'orientation', 'horizontal', 'position', lgd_pos);

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#Case 6

% Create the legend with LaTeX markup

lgd = legend([pl_1, pl_6, pl_s_1, pl_s_6, pl_s_3, pl_s_7], {'disc (impuls)', 'disc (step)', 'stoch (impuls)', 'stoch (step)', 'stoch1 (impuls) stoch (step)'}, 'Interpreter', 'latex', 'fontsize', 34, 'orientation', 'horizontal', 'position', [0.12 0.04 0.8 0.034]);

% Create a second line of text with a line break

lgd_text = 'stoch1 (impuls) \newline stoch (step)';

text(lgd.Position(1), lgd.Position(2) - 0.03, lgd_text, 'Interpreter', 'latex', 'FontSize', 34, 'HorizontalAlignment', 'center');

Answer 1

[Voss]

legend([pl_1, pl_6, pl_s_1, pl_s_6, pl_s_3, pl_s_7], ...
    {'disc (impuls)', 'disc (step)', 'stoch1 (impuls)', 'stoch1 (step)', 'stoch (impuls)', 'stoch (step)'}, ...
    'interpreter','latex', ...
    'fontsize',34, ...
    'NumColumns',4, ...
    'Orientation','horizontal')

[Rayan]

Fantastic! Thank you so much.

[Voss]

You're welcome!