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How can I iterate through a list of files using dlmread()?

Asked by Haydn Darragh on 19 Aug 2015
Latest activity Commented on by Haydn Darragh on 19 Aug 2015
Hello,
I am able to load all files and manually change the name of the files to access each on individually, however when I try to use a for loop that changes the name of the file in the form of a changing string, I get the error message below:
"Error using dlmread (line 119) The file 'file1' could not be opened because: No such file or directory
Error in EbnoVsRange (line 19) Zero(i) = dlmread(fname,',',[26 2 26 2]);"
This is after I have loaded the files in, one of which is called 'file1'
The code I'm using is below:
file1 = 'C:\Users\....\range1cm.csv';
file2 = 'C:\Users\....\range2cm.csv';
file3 = 'C:\Users\....\range3cm.csv';
file4 = 'C:\Users\....\range4cm.csv';
file5 = 'C:\Users\....\range5cm.csv';
for i = 1:1:10
fname=['file',num2str(i)]
Zero(i) = dlmread(fname,',',[26 2 26 2]);
end
Thank You

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1 Answer

Answer by David Legland on 19 Aug 2015
Edited by David Legland on 19 Aug 2015
 Accepted Answer

Hi,
The problem comes from you ask Matlab to open the file called 'file1', not the file whose name is stored in the variable file1.
In your case you can use the 'eval' function:
fname = eval(['file' num2str(1)]);
However, I would rather build the file name programmatically:
inputDir = 'C:\Users\...'
fname = fullfile(inputDir, sprintf('range%dcm.csv', i));

  1 Comment

This is great, thank you for your response. I have also implemented your other option for retrieving the files too. This will save many lines of code at the end of the day

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