finding skew angle of license plate
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following is the bit of code for finding skew angle in horizontal direction.. Can someone please explain ?
for i=-44:44
m=tan(i*pi/180);
for j=-r+1:r-1
for k=-c+1:c-1
if (round((m*(k))+j+r+r)<=0)
v=1;
elseif(round((m*(k))+j+r+r)>2*r-1)
u=1;
else
q=w(round((m*(k))+j+r+r),k+c);
z(j+r,i+45)=z(j+r,i+45)+ double(q);
end
end
end
end
2 Comments
Ashish Uthama
on 16 Dec 2011
Omikar, I formatted the code for you. (Please consider using the the '{} code' button in your next question to make it readable)
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