How to reply to a message?

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Fabi Boro
Fabi Boro on 17 Apr 2016
Edited: Walter Roberson on 18 Apr 2016
This is a general question for the mathworks.com webpage. I hope this is the right place to ask this question. I looked up for some information but couldn't find anything.
My problem is when I want to reply to a message I always get linked to "MathWorks Account - Edit Profile". Is this an error of the webpage or am I doing something wrong.

Answers (3)

Star Strider
Star Strider on 17 Apr 2016
What do you mean by ‘reply to a message’?
If you want to send a personal message to someone who has posted here, you will get linked to the person’s profile page. If the person allows personal messages, there will be a small ‘envelope’ symbol near the position for the person’s avatar. If the ‘envelope’ symbol is not there, you can see if the person has a similar profile page in the File Exchange. (Most have File Exchange personal message links because they want feedback on their File Exchange contributions.) Use that to send your message.
  6 Comments
Image Analyst
Image Analyst on 17 Apr 2016
So you went ahead and filled out the form and it still brings up a blank form? I'd call them on Monday about that. My guess is that it might need your email if you said you want to be updated, and since you didn't have it, it throws you into this screen. But since you say you updated it, but it's clearly not updating, then you'll need to talk with the Mathworks about it.
Fabi Boro
Fabi Boro on 18 Apr 2016
I have an email address and an organisation filled out. I just cleared it for the example because I thought it's not necessary to show.
Thanks for the effort!

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Image Analyst
Image Analyst on 17 Apr 2016
The mathworks.com web page - their home page - does not have message you can reply to on it. So I think you were doing something wrong. So exactly what page were you on, and what link did you click on?

Fabi Boro
Fabi Boro on 17 Apr 2016
When you open this link you'll see in the message header "Reply to this message" when I click this button a new website opens, MathWorks Account - Edit Profile - Edit community information. The only thing I can do now is do update my profile and nothing else, I don't get anywehre else
  4 Comments
Star Strider
Star Strider on 17 Apr 2016
Alan Weiss seems to have given you a comprehensive reply. If you did what he suggested and you continue to have problems, post here, quote that thread (with URL), and ask for specific additional information. Explain what you did since your original post, include (or attach) your code and other files as necessary, and describe what you still need help with.
Alan and others with applicable expertise in that area will likely reply if you state your question clearly and provide all necessary information.
Fabi Boro
Fabi Boro on 18 Apr 2016
Edited: Walter Roberson on 18 Apr 2016
I worked through all the documentations suggested bei Alan Weiss. This is how far I got:
function [xsolve,fval] = runnested(x0,X,t,Z,Y_corr,lb,ub)
[xsolve,fval] = lsqnonlin(@nestedfun,x0);
% Nested function that computes the objective function
function Y = nestedfun(xsolve)
Y_theo = (X.^2.*(xsolve(2) - t)./(xsolve(2)-Z).*(1 + xsolve(1).*(xsolve(2)-t))/(1 + xsolve(1).*(xsolve(2)-Z))).^0.5
Y = Y_theo(3) - Y_corr
end
end
x0 = [-10000 200] start point
xsolve = [a b] my control variables in one variable
-10.000 ≤ a ≥ 10.000
200 ≤ b ≥ 400
lb = [-10000 200] lower bound of xsolve
ub = [10000 400] upper bound of xsolve
X, Z are vectors with data
t is a constant
Y_corr are the values I want Y_theo to be optimized to
Following this documentation:
xsolve = ['a' 'b'] is a cell now
I couldn't figure out how to set up the linear programming to assign the lower/upper bounds to my variables. a and b are independently of each other.
Running through the code it gives me that:
Y_theo =
0 0 2.2134 0 0 0 0 0 0
0 0 2.4969 0 0 0 0 0 0
0 0 2.6830 0 0 0 0 0 0
0 0 2.2144 0 0 0 0 0 0
0 0 2.4936 0 0 0 0 0 0
0 0 2.6801 0 0 0 0 0 0
0 0 2.2166 0 0 0 0 0 0
0 0 2.4918 0 0 0 0 0 0
0 0 2.6782 0 0 0 0 0 0
Y =
-2.2339
-2.5204
-2.7078
-2.2349
-2.5188
-2.7075
-2.2374
-2.5182
-2.7077
Initial point is a local minimum.
Optimization completed because the size of the gradient at the initial point
is less than the default value of the optimality tolerance.
<stopping criteria details>
xsolve =
-10000 200
fval =
56.0237
Where are the mistakes? I have a hard time to transfer the documentations to my specific problem

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