Puzzler: Count unique nonzero periods in a timeseries without a for loop

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given: a signal as a time series
return: discrete number of times is is holds a nonzero position
For example:
given: [0,1,0.5,0.7,0,1]
return: 2
given: [0,1,0,0,0,.3,1,0,0,1]
return: 3
given: [0,1]
return: 1
is there a way to do this task in a vector manner as opposed to a for loop that counts nonzero periods as it encounters them and flicks a counter.

Accepted Answer

Azzi Abdelmalek
Azzi Abdelmalek on 19 Jul 2016
Edited: Azzi Abdelmalek on 19 Jul 2016
out=numel(strfind([0 logical(a)],[0 1]))

More Answers (1)

Image Analyst
Image Analyst on 19 Jul 2016
[~, numRegions] = bwlabel(yourVector ~= 0);

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