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Can I convert long binary strings into unique serial numbers of much shorter length?

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I’m generating a very large number of long binary strings, for example:
S1 = [0 0 1 1 0 0 0 0 0 0 1 0 1 1 0 0 0 ]
S2 = [1 1 0 0 1 1 0 0 0 0 0 1 0 1 0 0 1 ]
S3 =
Sometimes these strings are thousands of elements long and every time I generate a new string I would like to make sure that it is unique and has never been generated before. I could do this by simply storing all strings that has ever existed and using a function like ismember, isequal or something to compare every string to all previous strings, however, this takes a very long time and quickly becomes unfeasible as the list grows.
So I was wondering if there was a faster way of doing this. For example, could I convert every string into a unique serial number of much shorter length somehow so that S1 instead of being represented as a string became the number: 94237 (there is no logic behind this example number) and S 2 some other reasonably short number which perhaps would be much faster to compare uniqueness against than a long string? Is this possible and are there clever conventional ways of converting binary strings into unique serial numbers of minimal length? The serial number does not need to be backwards convertible into the string, all I need is to determine whether or not it is unique.

  2 Comments

Stephen Cobeldick
Stephen Cobeldick on 6 Sep 2016
Pick a hash function that suits your data and requirements:
Note that any hash loses information: hash functions may allow collisions between different data by giving them the same hash value.
Petter Stefansson
Petter Stefansson on 6 Sep 2016
Thank you for the tip. Would you happen to know of any hash function that is particularly well suited for binary data and/or is already build into matlab?

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Accepted Answer

Guillaume
Guillaume on 6 Sep 2016
Edited: Guillaume on 6 Sep 2016
Considering that encryptions keys are now getting to 2048 bits or more, 1000 bits is not that long.
How about grouping your bits in lumps of 64. converting that to 64 bits integer, and comparing these 64 bits numbers (with ismember indeed).
If it's not fast enough, then yes any hash function would work. Some, such as md5 are available on the file exchange or can be called directly from matlab using the java interface.

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Petter Stefansson
Petter Stefansson on 6 Sep 2016
Yes I found and tried some md5 hash generator scripts on the file exchange that seems to work just fine so far, they make the lookup significantly faster!
However, since this is a bit new to me and I don’t know how the algorithm generates the hash I have no idea how safe it is to use md5, if I start generating sequences of ones and zeroes and converting into md5 hashes, at what point is it reasonable to expect a collisions? Is there a risk after a mere few thousand sequences or is that risk astronomically small?
Guillaume
Guillaume on 6 Sep 2016
You're going to need to generate a LOT of numbers or be really unlucky before you see an md5 collision (as long as you don't deliberately try to create collisions).
And if you see a collision, you can simply compare the true binary vectors. 99.999999% you don't have collisions, so you guaranteed the two vectors are not identical with a fast hash comparison, and once in a blue moon you have a slower comparison.

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More Answers (1)

Thorsten
Thorsten on 6 Sep 2016
Edited: Thorsten on 6 Sep 2016
You said that you generate the numbers, but you do not mention any constraints on the generation. Without any constraints, just pick a number and append 1 to ensure that the numbers are unique.
If you do have constraints, it would be good to know them. hash functions are fine, but you cannot be 100% sure that there are no collisions, i.e., that you do not generate the same hash for the different inputs. It is just that the hash function tries so minimise the probability of such collisions.

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Thorsten
Thorsten on 6 Sep 2016
You can generate your first number of thousands of 1's and 0's
s
Then you generate your next unique number
s 1
and the next
s 1 1
and so one. All number are unique. And if you like you can randomly append 0 and 1.
Petter Stefansson
Petter Stefansson on 6 Sep 2016
If I understand you correctly this way of numbering is just an S followed by a sequence of ones that grows by one element every time I generate a new binary vector? So by the time I have generated a million sequences the identification string is a million elements long? I’m sure I must misunderstand you somehow because that seems unreasonable.
Thorsten
Thorsten on 6 Sep 2016
That's exactly what I've suggested. You didn't mention that you need millions of sequences. Do you know in advance an upper limit of the number of sequences you need?
Then you could generate these N unique sequences in decimal reprentation using
seq = randperm(N);
and convert to binary
n = ceil(log2(N))
binseq = dec2bin(seq, n);
and pick from the precomputed list of unique binary sequences, one after the other.

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