have to make a function and return an answer of how long before it passes a certain point. does not work. help needed.
13 views (last 30 days)
Show older comments
i have to make a function that look like this
n(t)=n(t-1)*(1+alpha*(1-n(t-1)/K))
and know when n(t) surpasses a certain point,N.
my code looks like this:
function tN = bacteriaGrowth(n0,alpha,K,N)
for t=1:20
n(t)=n(t-1)*(1+alpha*(1-n(t-1)/K));
n(0)=n0;
n(1)=n0*(1+alpha*(1-n0/K));
end
if n(t)>=N
tN=t
end
i just get an error in line 4, that doesn't explain what is wrong. help would be very appreciated.
1 Comment
Stephen23
on 26 Feb 2017
Edited: Stephen23
on 26 Feb 2017
"i just get an error in line 4, that doesn't explain what is wrong"
And that error is obviously so useless you want to keep it a secret. Please actually try to help us by giving editing your question and giving the complete error message. This means all of the red text.
When I tried running your code I got this error:
??? Undefined function or variable "n".
Error in ==> bacteriaGrowth at 3
n(t)=n(t-1)*(1+alpha*(1-n(t-1)/K));
Which is obviously not the same error that you are getting because you wrote that your error "doesn't explain what is wrong", whereas the error that I get does. And an internet search of that error message gives a thousand explanations of how to fix it.
Accepted Answer
Jan
on 26 Feb 2017
Please consider Stephen's advice and explain, what you observe and what you exactly want to calculate. I try it with a bold guess:
You have to start with n0 before you access n(t-1):
function tN = bacteriaGrowth(n0, alpha, K, N)
n = n0 * (1 + alpha * (1 - n0 / K));
t = 0;
while t < 20 && n < N
for t = 2:20 % Start at 2, because n(1) is defined already
n = n * (1 + alpha * (1 - n / K));
t = t + 1;
end
tN = t;
If you want to reply tN only, storing n in a vector is not useful.
Does this help you? If not, please explain the problem by editing the question, not in the sections for answers or comments. Thanks.
More Answers (0)
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!