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How do I find and replace strings in a cell array with numerical values?

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Brad
Brad on 4 Mar 2017
Commented: Brad on 4 Mar 2017
I've got the following 3 x 5 cell array;
10000.1110000000 20000.9000000000 100.450000000000 22445 'SET_THRESH'
20000.2220000000 20000.9000000000 200.670000000000 22445 'HOLD_THRESH'
30000.3330000000 20004.6000000000 300.890000000000 22445 'DELETE_THRESH'
I'm trying to come up with a technique where the strings in column 5 are automatically replaced with their numerical equivalents (SET_THRESH is 0, HOLD_THRESH is 2, DELETE_THRESH is 3). The resulting 3 x 5 cell array would look like this;
10000.1110000000 20000.9000000000 100.450000000000 22445 '0'
20000.2220000000 20000.9000000000 200.670000000000 22445 '2'
30000.3330000000 20004.6000000000 300.890000000000 22445 '3'
Is it possible to achieve the desired output using a combination of functions within a loop?

Accepted Answer

Walter Roberson
Walter Roberson on 4 Mar 2017
possible_threshes = {'SET_THRESH', 'HOLD_THRESH', 'DELETE_THRESH'};
thresh_vals = [0, 2, 3]
[tf, idx] = ismember(YourCell(:,5), possible_threshes);
YourCell(tf, 5) = num2cell( thresh_vals( idx(tf) ) );
Any entry that is unmatched will be left as a string.

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