change the element-by-element organization into a plane organization

Hello

I have an array <20000x1 struct> in element-by-element organization. Each of the 20000 entries has more than 30 fields.

I would like to change the element-by-element organization into a plane organization.

I found how to do it from plane to element-by-element ( http://www.mathworks.com/matlabcentral/answers/4581-deleting-the-i-th-entry-from-all-fields-of-a-struct) but I cannot figure out how to do it in the opposite way.

Could you help me, please?

Thank you very much

Claudia

[Claudia]

long time ago I found my own solution but forgot to put it here. So, here it is:

folder = ['/scratch ...']

fields = fieldnames (datastructold) ;

for f = 1:size(fields,1) ;

varname = genvarname(fields{f}) ;

extract = {datastructold.(varname)};

datastructnew.(varname) = extract ;

end

v = genvarname([ 'name' ]) % name for variable

S.(v) = datastructnew

save([ folder v '.mat' ] , '-struct' , 'S' ) ; % name for .mat

Answer 1

[Claudia]

long time ago I found my own solution but forgot to put it here. So, here it is:

folder = ['/scratch ...']

fields = fieldnames (datastructold) ;

for f = 1:size(fields,1) ;

varname = genvarname(fields{f}) ;

extract = {datastructold.(varname)};

datastructnew.(varname) = extract ;

end

v = genvarname([ 'name' ]) % name for variable

S.(v) = datastructnew

save([ folder v '.mat' ] , '-struct' , 'S' ) ; % name for .mat

Answer 2

[Walter Roberson]

struct2cell(), then either cell2mat() or expand the cell within a vertcat() or horzcat().

However, if the fields are not all exactly the same size or are of mixed numeric type involving more than one integer data type, then you are going to have problems.

[Claudia]

Hi Walter

Thank you for your answer. I tried what you suggested.

But for cell2mat all contents of the input cell array must be of the same data type.

And vertcat() and horzcat() did not change anything at all.

So, at the end I missed the step to get the structure with plane organization.

It would be nice if you could explain that step.

Thanks, Claudia

Answer 3

[Sean de Wolski]

So if this is a simple example of your struct:

S = struct('field1',num2cell(1:10),'field2',num2cell(repmat(pi,1,10)))

Then I would recommend using:

S2 = squeeze(struct2cell(S))

To now have a 2x10 cell array.