Divide a matrix with an array along a specific dimension
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A=rand(10,20,30);
B=[1:30];
I want to divide A with B along the third dimension. I got the required result using loop.
for ii=1:30
C(:,:,ii)=A(:,:,ii)/B(ii);
end
But is there any pre-defined function which does the same operation, which takes the dimension as a input along which we want to divide a matrix.
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Accepted Answer
Stephen23
on 16 Mar 2018
Edited: Stephen23
on 16 Mar 2018
Once you make the sizes compatible you can do this using standard methods without any loop. Use permute or reshape to get the correct size of B. For example In R2016b and later a standard rdivide will do this:
A ./ reshape(B,1,1,[])
bsxfun(@rdivide,A,reshape(B,1,1,[]))
More Answers (1)
Akira Agata
on 16 Mar 2018
How about using arrayfun ?
C = arrayfun(@(k) A(:,:,k)./B(k), 1:30,'UniformOutput',false);
C = cat(3,C{:});
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