# Operations between every 2 different elements in a cell?

3 views (last 30 days)
Xiaohan Du on 11 Jun 2018
Commented: Xiaohan Du on 11 Jun 2018
Hi all,
I have a cell like this:
K>> ur
ur =
4×3 cell array
{} {'-1 -1'} {1×201 cell}
{} {'1 -1' } {1×201 cell}
{} {'1 1' } {1×201 cell}
{} {'-1 1'} {1×201 cell}
I'd like to perform some operations between every 2 elements of the 3rd column of ur, manually be like this:
operation(ur{1, 3}, ur{2, 3}) % 1 and 2
operation(ur(1, 3), ur(3, 3)) % 1 and 3
operation(ur(1, 3), ur(4, 3)) % 1 and 4
operation(ur(2, 3), ur(3, 3)) % 2 and 3
operation(ur(2, 3), ur(4, 3)) % 2 and 4
operation(ur(3, 3), ur(4, 3)) % 3 and 4
The number of cell rows is not limited to 4. Is there a way to do this in a loop? Or whatever automatic? I think I just need to pick the correct index to perform the operation, but how?
Many thanks!
Edit: the operations should all be curly brackets:
operation(ur{m, 3}, ur{n, 3}) % m and n
##### 2 CommentsShowHide 1 older comment
Xiaohan Du on 11 Jun 2018
My mistake, it should all be curly brackets. Operation here is a function in my code, this function takes ur{m, 3} and ur{n, 3} and gives a matrix as a result.

Jan on 11 Jun 2018
Maybe you mean:
index = nchoosek(1:4, 2);
for k = 1:size(index, 1)
operation(ur{index(k, 1), 3}, ur{index(k, 1), 3});
end
Xiaohan Du on 11 Jun 2018
Thanks Jan!