I want to put this equation in MATLAB and write a report about it, I will need at least one graph, can anyone please give me with the code to do so?

2(y-1)y’ = 3t^2 + 4x + 2 
y(0)= -1

[Ameer Hamza]

This seems like a homework question, tell us what you have already tried? As a hint, look at ode45() .

[Walter Roberson]

Your y appears to be a function of both t and x. y' is ambiguous as to whether it is the partial derivative with respect to t or to x.

[Walter Roberson]

Also, because y is a function of both t and x, you cannot just say y(0)=-1 : you need to give y() at two parameters, one for t and the other for x.

[Brian Kenor]

That is very true Walter, I noticed there was a problem with that equation. The equation should be

 2(y-1)y’ = 3t^2 + 4t + 2 
 y(0)= -1.

I have followed through the link Ameer sent above and it is very insightful.

Thanks!

[Walter Roberson]

Sorry, Brian, I lost track of this question.

Answer 1

[madhan ravi]

syms y(t)

ode=2*(y-1)*diff(y)==3*t.^2+4*t+2

cond=y(0)==-1;

y(t)=dsolve(ode,cond)

fplot(y(t))

[Walter Roberson]

Yes, this looks reasonable.