index exceeds array bound meaning?
289 views (last 30 days)
Show older comments
Chaitanya Lakeshri
on 2 Sep 2018
Commented: Walter Roberson
on 28 Nov 2022
what is the meaning of index exceeds array bound
3 Comments
Walter Roberson
on 29 Mar 2022
You have
x =optimvar('x',2,'LowerBound',[0 0],'UpperBound',[5 5]);
so you say that x is a vector of 2 optimization variables. Your upper bound and lower bound are both vectors of length 2, which is consistent. x is not ambiguous: it really is length 2.
obj = x(1)^2 + x(2)^2 + x(3)^2;
but there you try to use x(3)^2 which would require that x be of length 3 or more.
Your constaints A, B, C all require that x has at least 3 elements.
x0.x = [0 0];
but that says that the initial value is a vector of length 2.
You need to decide whether your function involves 2 variables or 3 variables.
Accepted Answer
madhan ravi
on 2 Sep 2018
Edited: madhan ravi
on 2 Sep 2018
It means that the index number is more than the array elements.
An example:
x=[1:10]
x(11)
Your array has 10 elements but you try accessing the 11th element.
9 Comments
Umar Farooq
on 28 Nov 2022
Erro
Index in position 1 exceeds array bounds. Index must not exceed 1.
Error in New_Arya_Paris (line 27)
RI(i,j)=(di(i,j)+ di(i+1,j))/4000;
-------------------------------------------------------
Problm
w=[1.000 0.993 0.984 0.968 0.938 0.870 0.787 0.766 0.660 0.553 0.383 0.298 0.234 0.191 0.085]
d=[2.000 1.000 0.500 0.250 0.150 0.053 0.054 0.039 0.023 0.013 0.008 0.006 0.005 0.004 0.001]
di=d.*100
wi=(w.*1000)
ni=15
for j=1:1;
for i=1:(ni-1)
RI(i,j)=(di(i,j)+ di(i+1,j))/4000;
end
end
Walter Roberson
on 28 Nov 2022
You create a row vector, 1 row multiple columns. but index it as multiple rows with one column.
More Answers (1)
CECILIA ABASCAL FALAGAN
on 16 Aug 2020
Good morning,
I would like to obtain the real time of my computer to later carry out operations and obtain the elapsed time. I have used the "datetime" command but I can't separate the time from the date and use it for this purpose. Any suggestion? I would be very grateful
1 Comment
Walter Roberson
on 16 Aug 2020
Most of the time, you would use tic and toc to obtain elapsed time.
You can also use
tin = clock;
do your code
tout = clock;
how_long = etime(tout, tin) %seconds
You can also
tin = datetime();
do your code
tout = datetime();
how_long = seconds(tout - tin) %seconds
See Also
Categories
Find more on Matrix Indexing in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!