error in Euler method

2 views (last 30 days)
Momo
Momo on 16 Oct 2018
Reopened: Walter Roberson on 22 Dec 2018
. could you please, check my code I did not get as the following pic.
for i=1:length(T)-1
x1(i+1)=x1(i)+dX1*h;
x2(i+1)=x2(i)+dX2*h;
v1(i+1)=v1(i)+dX3*h;
v2(i+1)=v2(i)+dX4*h;
end
  2 Comments
James Tursa
James Tursa on 17 Oct 2018
Closing your question and deleting your code and comments is not appreciated on this forum since it does not help anyone else later on. Please keep your questions and comments intact for everyone to see. Thanks.
Momo
Momo on 17 Oct 2018
I have not received assistance that could be benefit to me or others. Thanks anyway.

Sign in to comment.

Accepted Answer

James Tursa
James Tursa on 16 Oct 2018
Edited: James Tursa on 16 Oct 2018
You need to recalculate the derivatives at each time step. So all of the stuff that goes into calculating dX needs to be inside of your for-loop. Which means that all of the equations for this calculation need to be indexed. E.g., this
r=x1-x2 ;
should be this
r=x1(i)-x2(i) ;
etc.
  4 Comments
James Tursa
James Tursa on 16 Oct 2018
Edited: James Tursa on 16 Oct 2018
So, when I wrote that you needed to have your derivative calculations inside of the for-loop, I was talking about your existing for-loop in your original posted code:
for i=1:length(T)-1
% Put all of your derivative calculations here
x1(i+1)=x1(i)+dX(1)*h;
x2(i+1)=x2(i)+dX(3)*h;
v1(i+1)=v1(i)+dX(2)*h;
v2(i+1)=v2(i)+dX(4)*h;
end
What you have done is create an additional for-loop (not my intention), and changed your original for-loop indexing (also not my intention). Instead, go back to your original for-loop indexing, and put your derivative code where I have the comment. Basically, at each step you need to recalculate the derivatives based on the current state.
James Tursa
James Tursa on 16 Oct 2018
Edited: James Tursa on 16 Oct 2018
Why are you using i=1:N instead of the original i=1:length(T)-1? Why are you overwriting dx1(i) and dx2(i) each step without doing the if-test part?

Sign in to comment.

More Answers (0)

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!