Integral vector .* sin(pi*x) error matrix dimensions must agree.
1 view (last 30 days)
Show older comments
Hassan Al_ma
on 18 Oct 2018
Commented: Star Strider
on 18 Oct 2018
I have the following code I try to find integral for function f the um is data vector (1X50). The problem is how can I used ingtral function to find integral for (vector .* sin(pi*x)), when I run code I received error "matrix dimensions must agree." any badoy can help me.
if true
L=1;
x = linspace(0, L, n);
fm=zeros(1,n);
for i=1:1
lam=i*pi;
f=@(x) um .* sin(lam * x ); % _um vector 1X50 double_
fm=fm+exp(lam^2*T)*sin(lam*x)*(2*integral(f,0,L));
end
end
0 Comments
Accepted Answer
Star Strider
on 18 Oct 2018
When in doubt, and if you do not intend matrix operations, vectorise every operation to do element-wise operations. Specifying 'ArrayValued',true in the integral call is also necessary here.
Try this:
fm = fm + exp(lam^2*T).*sin(lam*x).*(2*integral(f,0,L, 'ArrayValued',1));
2 Comments
More Answers (0)
See Also
Categories
Find more on Logical in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!