How can i allocate results in matrix with for loop?

i tried store my results of exp()... in matrix with for loop.

if you guys how would you do this?

Answer 1

[Stephen23]

This is MATLAB, so just get rid of the pointless loops entirely:

>> w = 0:4;
>> t = 0:9;
>> y = exp(t.*w(:).*1i)
y =

 Columns 1 through 5:

   1.00000 + 0.00000i   1.00000 + 0.00000i   1.00000 + 0.00000i   1.00000 + 0.00000i   1.00000 + 0.00000i
   1.00000 + 0.00000i   0.54030 + 0.84147i  -0.41615 + 0.90930i  -0.98999 + 0.14112i  -0.65364 - 0.75680i
   1.00000 + 0.00000i  -0.41615 + 0.90930i  -0.65364 - 0.75680i   0.96017 - 0.27942i  -0.14550 + 0.98936i
   1.00000 + 0.00000i  -0.98999 + 0.14112i   0.96017 - 0.27942i  -0.91113 + 0.41212i   0.84385 - 0.53657i
   1.00000 + 0.00000i  -0.65364 - 0.75680i  -0.14550 + 0.98936i   0.84385 - 0.53657i  -0.95766 - 0.28790i

 Columns 6 through 10:

   1.00000 + 0.00000i   1.00000 + 0.00000i   1.00000 + 0.00000i   1.00000 + 0.00000i   1.00000 + 0.00000i
   0.28366 - 0.95892i   0.96017 - 0.27942i   0.75390 + 0.65699i  -0.14550 + 0.98936i  -0.91113 + 0.41212i
  -0.83907 - 0.54402i   0.84385 - 0.53657i   0.13674 + 0.99061i  -0.95766 - 0.28790i   0.66032 - 0.75099i
  -0.75969 + 0.65029i   0.66032 - 0.75099i  -0.54773 + 0.83666i   0.42418 - 0.90558i  -0.29214 + 0.95638i
   0.40808 + 0.91295i   0.42418 - 0.90558i  -0.96261 + 0.27091i   0.83422 + 0.55143i  -0.12796 - 0.99178i

If you really want to use pointless nested loops, then try this:

y = nan(5,10);
for t = 0:4
    for w = 0:9
        y(t+1,w+1) = exp(t*w*1i)
    end
end

Answer 2

[madhan ravi]

y=zeros(6,10);  %change this
ctr=1; %before loop
y(ctr,:)=.... change this part
ctr=ctr+1;  % add this before last end (after the first end)- > inbetween two ends

[madhan ravi]

If my answer solved your problem make sure to accept the answer else let know.