Conditionally Defining a Variable using ODE45

1 view (last 30 days)
How could I take this code I'm using and conditionally define my variable 'p'? For example, I want p=0 everywhere except when 3<t<4, then I want p=1.2. Here is my code:
tspan=[1 7];A0=1;P0=1;g=1;p=0;B=0.15;
[t,x] = ode45(@(t,x) [-g*x(1) + p*x(1); -x(1)*x(2)+ B*x(2)], tspan, [A0 P0]);

Accepted Answer

Walter Roberson
Walter Roberson on 16 Feb 2019
you need to use three ode45 calls , once for the three cases (before 3, during the range, after 4)
  4 Comments
Thomas Veith
Thomas Veith on 19 Feb 2019
Okay, thank you. For the method your colleague suggests, how do I fully define my variable 'p'? It seems that this code only defines for the range from 3 to 4? How do I make sure it's also defined outside the range?
Walter Roberson
Walter Roberson on 19 Feb 2019
3 < t & t < 4 gives a logical result, false or true, but in most contexts those are treated as 0 and 1. So outside of 3 to 4, the test has a definite numeric value, of 0, and 0 * 1.2 is 0, so it has a well defined value of 0 outside of (3, 4) .
However, in general when you use this kind of construct, Something Times a Logical, you need to be careful in case the Something could be infinite, since infinity times 0 is nan rather than 0. Consider for example x(1) * (3 < t & t < 4) then if x(1) went to infinity there would be calculation problems outside of (3,4) . In your particular case of Something being the constant 1.2, that is not a problem, so just something to keep in mind when you start to use this construct for other purposes.

Sign in to comment.

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!