how reshape the separated signal to original signal ?

hi every one

If I have the following vectors

x= [1 2 -6 9 -7 8 -8 -5 2 4 -6 4 -4 -5 -7 6 10 2 3 7 -8 9 -8 -5 4 -6]

Xp=x(x>0)

Xn=x(x<0)

after separated the signal is transmitted

fr=[length(Xp), Xp, Xn]

then in the recevier Rx

rp=fr(2:fr(1)+1); % positive Rx

rn=fr(2 + fr(1):end); %negativ Rx

then I want to reshape the vector as original vectors

can any one help me

thank u very much

Answer 1

[KSSV]

YOu pick the indices and get what you want.

x= [1 2 -6 9 -7 8 -8 -5 2 4 -6 4 -4 -5 -7 6 10 2 3 7 -8 9 -8 -5 4 -6]
Xp=x(x>0) ; idxp = x>0 ; 
Xn=x(x<0) ; idxn = x<0 ;
% after separated the signal is transmitted 
fr=[length(Xp), Xp, Xn]
% then in the recevier Rx
rp=fr(2:fr(1)+1);       % positive Rx
rn=fr(2 + fr(1):end);   %negativ Rx

iwant = zeros(size(x)) ;
iwant(idxp) = rp ;
iwant(idxn) = rn ;

Note that, the above code can be optimized by using completely indices.

[abdullah qasim]

thank u very much bro