using 'fsolve'

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Harry Jones
Harry Jones on 21 Mar 2019
Edited: Harry Jones on 23 Mar 2019
I have the function f(x,y) = x.^(2-x.^(0.5))+y.^(2-y.^(0.5)) and I found the Jacobian and Hessian Matrices. Now I need to find the turning point using the function "fsolve" and stating its nature.
Can anyone help me?
Thanks in advance.
  1 Comment
Walter Roberson
Walter Roberson on 21 Mar 2019
The "turning points" are all the points where the derivative are 0.
You already have the derivative when you formed the Jocobian.

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Accepted Answer

Stephan
Stephan on 21 Mar 2019
Hi,
why not solve it symbolic:
syms f(x,y)
f(x,y) = x.^(2-x.^(0.5))+y.^(2-y.^(0.5));
[xsol,ysol] = vpasolve(diff(f,x) + diff(f,y) == 0, [x,y], [1 3; 1 3]);
zsol = subs(f,[x,y],[xsol,ysol]);
% plot results
fsurf(f)
hold on
scatter3(double(xsol),double(ysol),double(zsol),'or','LineWidth',2,'MarkerFaceColor','r')

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