## remove zeros from sinc function

### Gaurav Sharma (view profile)

on 17 May 2019
Latest activity Answered by Sulaymon Eshkabilov

on 18 May 2019

### Sulaymon Eshkabilov (view profile)

Hi there,
I am trying to observe the behaviour of the fourier trasform of the sinc function if some of its zeros will be removed. Normally, the sinc function will lead us to rectanglular function in fourier domain, but when I am trying to remove the zeros at 'pi' it is not showing anything due to NaN or infinite. May I request you to pls tell me how to deal with such problem?
Fs=42;Ts=1/Fs;
t=-1:Ts:40*Ts-Ts;
f=5;
y=sinc(t*f)/(1-5*t/(0.9)*pi);
figure;
plot(t,y);
xlabel('x');
ylabel(' magnitude');
fy=fft(y);%figure;
% plot(fy)
fy = fftshift(fy);figure;
plot([abs(fy)])%;angle(fy);real(fy);imag(fy)]','*')

Jan

### Jan (view profile)

on 17 May 2019
It is easier to read, if you include the code directly. Therefore I've copied it from the attachment.
"it is not showing anything due to NaN or infinite" - what is "it" here?
Gaurav Sharma

### Gaurav Sharma (view profile)

on 18 May 2019
"the plot"- is not showing any thing... no plot.... just blank screen

### Sulaymon Eshkabilov (view profile)

on 18 May 2019

clearvars; close all
Fs=42;Ts=1/Fs;
t=-1:Ts:1;
f=5;
y=sinc(t*f)./(1-5*t/(0.9)*pi);
figure;
plot(t,y), xlabel('t'), ylabel(' y(t)'); title('Time domain analysis ')
L = length(t); Nblock = 256;
Y = fft(y, Nblock)/L;
f = Fs/2*linspace(0,2, Nblock/2+1);
figure;
plot(f, 2*abs(Y(1:Nblock/2+1))), title('Discrete FFT')
fY = fftshift(Y);figure;
plot(f, 2*abs(fY(1:Nblock/2+1))), title('Shift zero frequency')
figure, plot([angle(fY);real(fY);imag(fY)]','*')
title('Phase angle, Real & Imag components of Shift zero frequency')