# could anyone help me to solve the issue with respect to the code

1 view (last 30 days)
jaah navi on 18 Jun 2019
Answered: Stephen Cobeldick on 18 Jun 2019
code:
A=1:7
B=length(A)
idx=randperm(B,1)
disp(idx)
the above code run one time and it displays idx value.
Could anyone help me to run the above code 5 times and for each time idx value should needs to be different.

James Tursa on 18 Jun 2019
The syntax of a for-loop is:
for k=1:5
end

#### 1 Comment

jaah navi on 18 Jun 2019
code:
for k=1:5
A=1:7;
B=length(A);
idx=randperm(B,1);
disp(idx)
end
when i run the code it gives the same idx for some run.
what i actually need is it should be different for each run.

Soumya Sinha on 18 Jun 2019
I assume that for this case, since you only want idx value to change and not the values of A or B
A = 1:7;
B=length(A);
for i = 1:5
idx = randperm(B,1);
disp(idx);
end

jaah navi on 18 Jun 2019
ok.But the idx remains the same for more than one run when i run the code
idx = 1
idx = 1
idx = 1
idx = 7
idx = 4
What i actually need is idx should be different for each run.But with respect to the above result idx remains the same for three run .Could you please help me on this.
Soumya Sinha on 18 Jun 2019
That's a perfectly normal behaviour, you might get same numbers on some occasions, when I tried I got all different numbers in some cases and I few repeating. Moreover, randomness wouldn't ensure uniqueness in your answer.

Stephen Cobeldick on 18 Jun 2019
"What i actually need is idx should be different for each run"
The easiest way is to define them before the loop, e.g.:
A = 1:7
N = numel(A)
V = randperm(B,N)
for k = 1:N
A(k)
V(k)
end