could anyone help me to solve the issue with respect to the code

code:

A=1:7
B=length(A)
idx=randperm(B,1)
disp(idx)

the above code run one time and it displays idx value.

Could anyone help me to run the above code 5 times and for each time idx value should needs to be different.

Answer 1

[James Tursa]

The syntax of a for-loop is:

for k=1:5
    % your code here
end

[jaah navi]

code:

for k=1:5

A=1:7;

B=length(A);

idx=randperm(B,1);

disp(idx)

end

when i run the code it gives the same idx for some run.

what i actually need is it should be different for each run.

Answer 2

[Soumya Sinha]

I assume that for this case, since you only want idx value to change and not the values of A or B

A = 1:7;
B=length(A);
for i = 1:5
    idx = randperm(B,1);
    disp(idx);
end

[jaah navi]

ok.But the idx remains the same for more than one run when i run the code

idx = 1

idx = 1

idx = 1

idx = 7

idx = 4

What i actually need is idx should be different for each run.But with respect to the above result idx remains the same for three run .Could you please help me on this.

[Soumya Sinha]

That's a perfectly normal behaviour, you might get same numbers on some occasions, when I tried I got all different numbers in some cases and I few repeating. Moreover, randomness wouldn't ensure uniqueness in your answer.

Answer 3

[Stephen23]

"What i actually need is idx should be different for each run"

The easiest way is to define them before the loop, e.g.:

A = 1:7
N = numel(A)
V = randperm(B,N)
for k = 1:N
    A(k)
    V(k)
end