why im not able plot graph in 1 sec window of 16 sample

clc;clear all; close all;

A=1;
x=0:0.1:1;
sample=16;
y=A*sin((2*pi./sample)*x)


figure
plot(x,y)

[KALYAN ACHARJYA]

"in 1 sec window of 16 sample"

Can you elaborate it?

[germanbrain common]

In one sec window i have to plot sine wave with 16 points.

[dpb]

x=linspace(0,1,16);
y=A*sin(2*pi*x);
plot(x,y)

[germanbrain common]

thnak you

Answer 1

[Image Analyst]

You didn't have anough points to see the sine wave so all you see is a traingle wave. Increase the number of points and use linspace():

numPoints = 50; % Whatever
Amplitude = 1;
t = linspace(0, 1, numPoints);
period = 0.4; % Seconds -- whatever you want;
y = Amplitude * sin((2*pi./period) * t)
plot(t, y, 'bo-', 'LineWidth', 2, 'MarkerSize', 9)
grid on;
xlabel('Time', 'FontSize', 13);
ylabel('Y', 'FontSize', 13);
title('Sine Wave', 'FontSize', 13);

[germanbrain common]

thank you, but one question i am having here here my input signal is 1 sec or 1hz fre and what about sampling frequnecy here??

Fs is how much?

PS: I need one full cycle in 1 second,in your plot i can se 2.5 cycle.

[KALYAN ACHARJYA]

Change the period value, and see the results.

[Image Analyst]

fs (omega) is (2*pi/period). For a 1 second, 1Hz chunk of signal, you'll have one wave of the sine wave. You can pick whatever sampling rate you want. Of course the higher it is, the more accurately you'll draw the signal.