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Placing a constant through a column

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Imagine this
A=(1:30)';
B=(31:60)';
C=(61:90)';
D=[A B C];
S = numel(B);
xx = reshape(B(1:S - mod(S, 3)), 3, []);
BB = sum(xx, 1).' / 3;
F=[A B C BB];
You will notice F is not possible because BB has just 10 variables (Dimensions of arrays being concatenated are not consistent.)
What I need to do is make each value in BB constant for 3 rows so that F can become possible.

Accepted Answer

madhan ravi
madhan ravi on 28 Aug 2019
repmat(BB,3,1)
  3 Comments
DARLINGTON ETAJE
DARLINGTON ETAJE on 28 Aug 2019
Thank you...you're such a blessing

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