Can not get row vector to be 1,5

I have written code to generate random numbers within a constrant and I just want the end result to be a row vector of 5 different times, not 6 different vectors adding one until it reaches 1,6. What do I need to change?

n=0;
for a=89:0.5:91.5;
    n=n+1;
    V(n)=2*rand+a
end 

Answer 1

[Adam Danz]

First, here's the correct way to set up the loop. Avoid the n=n+1 approach in for-loops because for-loops are designed to iterate that way.

a = 89:0.5:91.5;
V = nan(size(a)); 
for i = 1:numel(a)
    V(i)=2*rand+a(i); 
end 

Or, better yet, the vectorized version that does the entire thing in 1 line

V = 2 * rand(size(a)) + a;

But since 'a' contains 6 values, V will also contain 6 values. If you want 5 values, you'll need to redefine a.

Answer 2

[Ridwan Alam]

Because a=89:0.5:91.5 gives you a vector of length 6

n=0;
V = [];
for a=89:0.5:91
    n=n+1;
    V(n)=2*rand+a
end 

[Ridwan Alam]

Hi Dylan, please accept the response as an answer if it works. Thanks!