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why the legend show wrong lines ?

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why is the legend of my plot showing the wrong data ? . I am doing plot of this file (DATA_LIM_43_892Khz ) . but for some reason it shows the wrong legend why ?
I_real=real_data_ADC*(19.6e-3)/(100*15e-3); %%real current
real_data_IN_driver=ADC_data_lim43.real_data_IN_driver; %% real gate signal
t=(1/f_RD_not)*(1:length(real_data_ADC));%% time
plot(t,I_real,' red -- d '); %% plot--> of I_real
hold on ;
plot(t,43*(19.6e-3)/(100*15e-3),' black '); %% plot--> of boundery limit
hold on ;
plot(t,100*(19.6e-3)/(100*15e-3)*real_data_IN_driver,' green -- d '); %% plot--> real gate signal
title([' I_1=' num2str(43*(19.6e-3)/(100*15e-3)) '[A]']);
legend ('I_{real}','boundery limit','real gate signal');
as you can see the legend show for some reason wrong data, is this a a bug of matlab ?

Accepted Answer

David Goodmanson
David Goodmanson on 22 Dec 2019
Edited: David Goodmanson on 22 Dec 2019
Hi tomer,
try replacing
plot(t,43*(19.6e-3)/(100*15e-3),' black '); %% plot--> of boundery limit
plot(t,43*(19.6e-3)/(100*15e-3)*ones(size(t)),' black '); %% plot--> of boundery limit
and 'hold off' is never a bad idea when you are done adding stuff to the plot.
tomer polsky
tomer polsky on 22 Dec 2019
thank you it works , could you explain why does it works ? or just take it as granted .
David Goodmanson
David Goodmanson on 22 Dec 2019
HI tomer,
it works because of the following:
x = 1:100;
y = .23;
z = .23*ones(1,100);
grid on
grid on
The first plot does not give you a trace, but the second one does.
Your original pliot is similar to fig 1, in that it has a scalar y and does not show a black trace. In this situation the intent to produce a flat trace seems clear enough, and Mathworks could have chosen to supply all the constant y values and produce a trace. But for whatever reason they decided not to do that. So to get the trace you have to supply all the values as in fig.2.
In your original plot, the fact that there is a linetype specified, but no trace is produced, seems to confuse the legend command.

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