Conversion to logical from sym is not possible. I want the first argument to be a logical argument which has && for non symbolic variables, In a piecewise function.
Show older comments
Hi,
I'm trying to execute this piecewise function
a = 10;
b = 4;
c = 2;
mu1 = 1;
sig1 = 0.5;
pdf1(x) = piecewise( a == 0 && b < 0 , -(1/(b*exp((c1 - x + b*mu1)^2/(2*b^2*sig1^2))*sqrt(2*pi)*sig1)),...
a == 0 && b > 0, 1/(b*exp((c1 - x + b*mu1)^2/(2*b^2*sig1^2))*sqrt(2*pi)*sig1),...
a ~= 0 && (-b^2 + 4*a*c1 - 4*a*x) < 0,(exp((b - sqrt(b^2 - 4*a*c1 + 4*a*x) + 2*a*mu1)^2/(8*a^2*sig1^2)) + exp((b + sqrt(b^2 - 4*a*c1 + 4*a*x) + 2*a*mu1)^2/(8*a^2*sig1^2)))/(exp((b^2 + 2*a*b*mu1 + 2*a*(-c1 + x + a*mu1^2))/(2*a^2*sig1^2))*sqrt(2*pi)*sqrt(b^2 + 4*a*(-c1 + x))*sig1),...
0);
for which i get the error Conversion to logical from sym is not possible. I realised this is because the first argument cannot have && or ||, however for my application its critical for this to be present. Any help is appreciated. TIA.
Accepted Answer
More Answers (1)
Walter Roberson
on 3 Feb 2020
(a == 0 && b < 0) == sym(true)
piecewise cannot accept a logical value as the first parameter, but compare to symbolic true works.
sym(a == 0 && b < 0)
just might work, but in some code I was doing recently sym() of the condition failed and I had to compare to sym(true)
1 Comment
Josyula Gopala Krishna
on 3 Feb 2020
Categories
Find more on Sudoku in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!