matrix dimension mismatch problem

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Debasish Mishra
Debasish Mishra on 27 Jun 2020
Commented: Star Strider on 27 Jun 2020
hiii
i have an issue of matrix dimension mismatch..i have this following code.
R=1:1:500;
d=[1 2 3 4];
delB=1;
Bmn=1;
a=1+((delB*d)-(Bmn*d./Rb)).^2;
b=1+(delB*d).^2-(Bmn*d./Rb).^2;
c=1+((delB*d)+(Bmn*d./Rb)).^2;
hmn=1.414*kpqt^2*d*((1./(sqrt(a.*(b+sqrt(a.*c)))))+(1./(sqrt(c.*(b+sqrt(a.*c))))));
XT=tanh(hmn*L);
This is showing matrix dimention mismatch.
plz help me out..
thank u in advance.

Answers (2)

madhan ravi
madhan ravi on 27 Jun 2020
d = (1:4).';

Star Strider
Star Strider on 27 Jun 2020
The assignment to ‘Rb’ appears to be missing. Since you are using element-wise division wih it, it appears to be a vector, so I created it as a random (1x4) vector to match ‘d’. (Also, ‘kpqt’ and ‘L’ are missing, although they appear to be a scalars.)
Assuming that ‘Rb’ is also a (1x4) vector, do element-wise multiplication:
hmn=1.414*kpqt^2*d.*((1./(sqrt(a.*(b+sqrt(a.*c)))))+(1./(sqrt(c.*(b+sqrt(a.*c))))));
↑ ← HERE
If the undefined variables have different row and column sizes than I assumed here, my Answer may need to change.
  2 Comments
Debasish Mishra
Debasish Mishra on 27 Jun 2020
thanx for responding.actually i wrote Rb to be R by mistake.R and Rb both are same.
Star Strider
Star Strider on 27 Jun 2020
My pleasure!
In that situation, you also need to transpose either ‘d’ or ‘R’ (although not both).
My original Answer remains valid with those changes, since that multiplication needs to be element-wise either way.
.

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