how will use nested loop

hello my problem is that i have 11 value for any variable suppose i=1:11 and have another variable suppose b=2:12 also has 11 values now my question is that i want to find out value for i=1 for z=i*b total 11 values and for i=2 another 11 value of z and so on how i can use nested loop

3 Comments

Image Analyst
Image Analyst on 18 Dec 2012
Edited: Image Analyst on 18 Dec 2012
It's not clear what you want. Please give an example with 2 11-element arrays, a and b, and what output(s) you want.
for i=1 I want 11 values of i*b in one row for i=2 I want 11 values of i*b in one row for i=3 I want 11 values of i*b in one row AND SO ON..............
Yes, and all of the Answers so far give you that.

Sign in to comment.

 Accepted Answer

try this:
z = zeros(11,11);
for a=1:11
for b=2:12
z(a,b)=a*b;
end
end
z(:,1)=[];

2 Comments

You declare z as 11 x 11, but then you use it as 11 x 12.
Because of the way MATLAB handles assignments to non-existant locations, this will work, but it does indicate a logic fault on your part.
@walter..I agre your point..

Sign in to comment.

More Answers (3)

Babak
Babak on 18 Dec 2012
Z = zeors(11,11);
for i=1:11
for b=2:12
z=i*b;
end
end

4 Comments

You would need to change the assignment to be
z(i,b-1) = i * b;
thanks this shows right answer
sir now if my varible i=0.1:.11 and b also in point then how it will save
If the number you're multiplying by is a fractional number, like 0.1 or 0.11 then you'll have to separate your index from your number, like I think you originally had in your message where you had a and b instead of i and b. You could just make the loop index from 1 to 11 and then create the array index from it like arrayIndex = i / 10 and then use arrayIndex in z() or wherever.

Sign in to comment.

Code golf:
z=i'*b

1 Comment

Provided "i" is not complex, which it normally is ;-)

Sign in to comment.

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!