finding the number of consecutive data

Hi,

I have a vector of 5000 obeservations containing nan values and prices. How can I tell if this vector contains 60 consecutive prices without any nan interruption?

Answer 1

[Thorsten]

This should do the job:

obs1 = observations(1);
Ncons = 1; 
for i = 2:numel(observations)
  if observations(i) == obs1
    Ncons = Ncons + 1;
    if Ncons == 60, break; end
  else
    obs1 = observations(i);
    Ncons = 1;
  end
end

if Ncons == 60
  disp('60 consecutive prices found.')
end