Simpson's 1/3 Rule

if mod(n,2) == 1

disp('Simpsons Rule cannot be applied when an odd number of intervals is chosen')

return

else

int = (n-2)/2;

Coefficients = [1, repmat([4 2],1,int),4,1];

end

I am using the loop above to create the coefficents required to apply Simpson's 1/3 rule but I keep getting an error at the end of my code that says," Unable to perform assignment because the left and right sides have a different number of elements." I feel that the error is caused by the repmat statement which is creating a row vector that is too large. My output vector is supposed to have 5 values if this helps. Let me know if you need additional information and thank you in advance!!

[VBBV]

is n an scalar or vector ?

[Jack Harker]

n is an integer

[Jack Harker]

n is the number of intervals used for Simpson's Rule.

[KALYAN ACHARJYA]

Once I checked, I couldn't get any such error, by passing different n value (Assumed n is single value)

n=.....? Define n here 
if mod(n,2) == 1
  disp('Simpsons Rule cannot be applied when an odd number of intervals is chosen')
  return 
else
  int = (n-2)/2;
  Coefficients = [1, repmat([4 2],1,int),4,1];      
end

[Abhishek Kumar]

Hi Jack, the portion of code you have shared has no issues. In the problem statement you are refering to a loop but the code you have shared has no loops. Could you please share the code and exact error you are getting so that we could help you better?