Average of 10 images

Hi;

I read a series of images and I want to calculate their average I've written

this code :

I=zeros(size(Io))
for i=1:10
  image{i}=im2double(imread(['0.1s_',num2str(i),'.tif']));
  I=I+image{i}
end;
I=I./10;

am I right ? knowing that it gives a result

Answer 1

[Image Analyst]

No, it's not. For one thing, don't use image as the name of a variable since it's the name of a built-in function. And no reason to store them all and use a cell array.

I0 = imread('0.1s_1.tif')
sumImage = double(I0); % Inialize to first image.
for i=2:10 % Read in remaining images.
  rgbImage = imread(['0.1s_',num2str(i),'.tif']));
  sumImage = sumImage + double(rgbImage);
end;
meanImage = sumImage / 10;

[Alan]

Hi; I tried the code which was modified on the basis of your code.

the code:

amg = imread('1.jpg'); % 1.jpg is one of 10 images
[a,b,c]=size(amg); 
dst_img=zeros(a,b,c); 
for k=1:10
    filename=[num2str(k), '.jpg'];
    d=imread(filename, 'jpg');
    dst_img=dst_img+double(d);
end

dst_img=dst_img/k;

dst_img=uint8(dst_img);
figure;imshow(dst_img);title('Average');

However, the result became more blured than input images.

The scene was still and the camera was still.

Can you tell me how to solve this problem?

Thanks.

[Image Analyst]

The images must be in slightly different positions, despite you thinking they aren't. The way around it is to call imregister() to align the images before summing.

[CS]

and how can we do that? put imregister() before the imread?

By the way i was trying to find moving object so i thought of finding the background and then subtract, do you know a better way to do that?

[Walter Roberson]

You need a base image such aas the first in the series . Then after every imread you would register the new image against the base image and add in the aligned version of the new image .