MATLAB Answers

plot phase angle in radian

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Shreen El-Sapa
Shreen El-Sapa on 8 Aug 2021
Commented: Walter Roberson on 9 Aug 2021
subplot(2,2,1)
%chi=1; alpha=2; lambda=0.25
%eta=0
p1=0.00139;
%eta=10
p2=-0.01262;
theta_rad = p1*pi/180; % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$\chi=1.0, \quad \eta=0.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%==========================================================
subplot(2,2,2)
theta_rad = p2*pi/180; % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$ \chi=1.0, \quad \eta=10.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
subplot(2,2,3)
%alpha=2; lambda=0.25
%eta=0
p3=0.02877;
%eta=10
p4=0.25253;
theta_rad = p3*pi/180; % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$\chi=10.0, \quad \eta=0.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
subplot(2,2,4)
theta_rad = p4*pi/180; % Degrees-To-Radians
polar(theta_rad, 'r.')
%title('Phase Angle')
title('$ \chi=10.0, \quad \eta=10.0$','Interpreter','latex','FontSize',10,'FontName','Times New Roman','FontWeight','Normal')
  6 Comments
Walter Roberson
Walter Roberson on 9 Aug 2021
To be more correct, the yellow numbers are linear spaced from 0 to the maximum value you asked to plot.

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Answers (1)

Walter Roberson
Walter Roberson on 9 Aug 2021
If the question is about switching the polar plot degrees to radians, then change your calls to polar() to instead be calls to polarplot(), and set the option 'ThetaAxisUnits', 'radians'

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