Calculate the probability that at least two people in a group share the same birthday. Given an integer input n, return to 0.015 (1.5%) precision the probability of this being the case. Assume that every day is equally probable as a birthday and ignore the leap year.
Example:
Input: 1 Output: 0.00
Input: 366 Output: 1.00
Solution Stats
Problem Comments
3 Comments
Solution Comments
Show comments
Loading...
Problem Recent Solvers103
Suggested Problems
-
Find the alphabetic word product
3457 Solvers
-
Construct a string from letters and counts
146 Solvers
-
Back to basics 12 - Input Arguments
620 Solvers
-
555 Solvers
-
Create a square matrix of multiples
495 Solvers
More from this Author7
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
I assume n is the number of people in the room.....
Although I got the solution, in the case of n=100, however, it results in 1.000, which means there MUST be at least two people share their birthday in a group of 100. Am I missing something here?
In case n=100 the exact probability is 0.999999692751072 therefore it could happen (although it is very unlikely) that no one shares the same birthday