Problem 1433. Mirror Image matrix across anti-diagonal

Created by Chintan

Solve Later

{"relationships":[{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/document","targetMode":"","relationshipId":"rId1","target":"/matlab/document.xml"},{"relationshipType":"http://schemas.mathworks.com/matlab/code/2013/relationships/output","targetMode":"","relationshipId":"rId2","target":"/matlab/output.xml"}],"parts":[{"partUri":"/matlab/document.xml","relationship":[],"contentType":"application/vnd.mathworks.matlab.code.document+xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\"?>\n<w:document xmlns:w=\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\"><w:body><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>Given an input number x, create a mirror image matrix 'Y' across the anti-diagonal. For example, if x=3,</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"code\"/></w:pPr><w:r><w:t><![CDATA[ Y = [1 2 3;\n      2 3 2;\n      3 2 1]]]></w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"text\"/></w:pPr><w:r><w:t>If x=4,</w:t></w:r></w:p><w:p><w:pPr><w:pStyle w:val=\"code\"/></w:pPr><w:r><w:t><![CDATA[ Y = [1 2 3 4;\n      2 3 4 3;\n      3 4 3 2;\n      4 3 2 1]]]></w:t></w:r></w:p></w:body></w:document>"},{"partUri":"/matlab/output.xml","contentType":"text/xml","content":"<?xml version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\" ?><embeddedOutputs><metaData><evaluationState>manual</evaluationState><layoutState>code</layoutState><outputStatus>ready</outputStatus></metaData><outputArray type=\"array\"/><regionArray type=\"array\"/></embeddedOutputs>"}]}

Solve

Solution Stats

188 Solutions
111 Solvers

Last Solution submitted on Aug 04, 2020

Last 200 Solutions

Problem Comments

Solution Comments

Solution 232886

3 Comments

3 Comments

Chintan on 19 Apr 2013

How does this solution generate such less size inspite of using so many functions?

Paul Berglund on 21 Apr 2013

The way Cody scores things, a string is just a string, even if it is basically executable code. So there are tricks you can do with regexp or str2num to make your score a lot lower than it otherwise would be.

Chintan on 23 Apr 2013

Ok, Thanks for information.

Problem Recent Solvers111

Problem Tags

diag basics

Problem 1433. Mirror Image matrix across anti-diagonal

Solution Stats

Last 200 Solutions

Problem Comments

Solution Comments

Problem Recent Solvers111

Suggested Problems

More from this Author10

Problem Tags

Problem 1433. Mirror Image matrix across anti-diagonal

Solution Stats

Last 200 Solutions

Problem Comments

Solution Comments

Problem Recent Solvers111

Suggested Problems

More from this Author10

Problem Tags

Players