2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder.
What is the smallest positive number that is evenly divisible by all of the numbers from 1 to input number?
Thank you to Project Euler Problem 5
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Aurelien Queffurust
on 20 Apr 2012
FYI: we cannot execute "matlabpool open" on the labs. ;)
Solution Comments
2 Comments
blaat
on 14 Feb 2012
What it does: it finds the maximum number of occurrences for each prime number smaller than x in the factorisations of the numbers 1:x (e.g., for x = 10, the maximum number of occurrences for 2 is 3, since 2*2*2 = 8). If the product of all prime factors taken to the power of their maximum # of occurrences is then taken, the smallest number that is divisible by 1:10 is obtained. So for x = 10: 2 * 2 * 2 * 3 * 3 * 5 * 7 = 2520.
Alfonso Nieto-Castanon
on 14 Feb 2012
nice
1 Comment
Franck Dernoncourt
on 3 Feb 2012
This code works but the server is too slow...
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4 players like this problem
4 players like this problem