In MATLAB, you create a vector by enclosing the elements in square brackets like so:
x = [1 2 3 4]
Commas are optional, so you can also type
x = [1, 2, 3, 4]
Create the vector
x = [1 2 3 4 5 6 7 8 9 10]
There's a faster way to do it using MATLAB's colon notation.
Solution Stats
Problem Comments
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37 Comments
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34 older comments
A M Aditya
on 31 May 2013
Nice problem
Thara Jose
on 8 May 2015
nice
SUBROTA HALDER
on 1 Sep 2016
This is very easy thing
Haitong Ye
on 26 Oct 2016
Great!
Kensuke Fujita
on 5 Nov 2016
nice
Jared Candelaria
on 6 Dec 2016
Easy problem! Great!
Eric Saunders
on 7 Dec 2016
Love it!
Eric Saunders
on 7 Dec 2016
nice
Reenu Thomas
on 13 Dec 2016
Very interesting!
Dov Stochel
on 13 Dec 2016
Great beginner problem!
Muhammad M Sahari
on 20 Dec 2016
nice
Gan Wee Ting
on 20 Dec 2016
nice
sim yoke meng
on 20 Dec 2016
nice
nour eddin
on 24 Dec 2016
nice
Adi Zabidi
on 27 Dec 2016
nicer
Kunwar Abdul Rahman
on 27 Dec 2016
nice
Nadhirah Nordin
on 28 Dec 2016
great
Muhammad Aliff Ibrahim
on 29 Dec 2016
good start
WAI KIT CHIN
on 19 Jan 2017
very good
Ennio Condoleo
on 24 Apr 2017
1:10
jamboy676
on 11 Jun 2017
the solution is well used by day to day users in matlab
tanmoy mulo
on 14 Aug 2017
a=1:10
Antonio Natar
on 27 Sep 2017
[1:1:10]
zhen lei
on 10 Oct 2017
It is so easy.Don't you think?
Muhammad Tanveer
on 21 Oct 2017
what is difference between 123456 and 1 2 3 4 5 6 vectors?
Mohamed Atyya
on 30 Oct 2017
good
Christian Harman
on 30 Nov 2017
Yeah, I personally like the colon operator for creating vectors!
Miklós Csécsi
on 23 Sep 2018
@Muhammad Tanveer: if you take 123456 (without commas, semicolons or spaces), it is one (huge) number.
You can create a vector both by enclosing the elements in square brackets like v=[1 2 3 4 5] or using commas, like v=[1,2,3,4,5]. They mean the very same: a vector (matrix) of 1 row and 5 columns. It is up to you.
If you used a semicolon (;), then v=[1;2;3;4;5] means something else: a vector of 5 rows and one single column.
anas anas
on 4 Feb 2019
awesome!
anas anas
on 4 Feb 2019
awesome!
anas anas
on 4 Feb 2019
awesome!
anas anas
on 4 Feb 2019
awesome!
anas anas
on 4 Feb 2019
awesome!
anas anas
on 4 Feb 2019
awesome!
Michal Halon
on 10 Apr 2019
Great idea to learn colon notation! Thanks!
Jacob Farrell
on 13 Apr 2019
cool
YIFEI ZHANG
on 15 May 2019
Why did I copy the code to the matlab editor and run it but the command line window says I didn't define a function or variable?
Solution Comments
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1 Comment
DIMI EKONGA NZELLY
on 25 Jun 2019 at 11:47
very easy
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1 Comment
Joey Chan
on 16 May 2018
How come?
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1 Comment
M W
on 4 Mar 2018
linspace gives you a smaller size :)
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1 Comment
Aasim Ullah Jan
on 29 Jan 2018
is it ok
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1 Comment
Tevin Mostoller
on 2 Dec 2017
Great problem
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2 Comments
nadhirahjasri
on 20 Sep 2017
wow very fun!
Antonio Natar
on 27 Sep 2017
[1:1:10]
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1 Comment
Matthias Witkowski
on 8 Aug 2017
why not
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2 Comments
Matthew Jones
on 28 Feb 2017
Nice. What is the difference between this vector and x = linspace(1,10,10)?
MathReallyWorks
on 22 May 2017
Hello Matthew Jones,
Linspace is similar to the colon operator ":", but gives direct control over the number of points.
In x = linspace(1,10,10) you directly enter the number of points and the function generates equally spaced vector but when you use ":" operator, you need to mention step size.
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1 Comment
fahad aljabal
on 29 Dec 2016
.
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1 Comment
TAYALAN SIVALINGAM
on 28 Dec 2016
good job
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1 Comment
David Verrelli
on 3 Sep 2018
This user (mohamed elbesealy) appears to have gamed the system, with fraudulent "likes" of this unremarkable solution submitted by 'sock-puppet' accounts. —DIV
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1 Comment
David Verrelli
on 3 Sep 2018
This user (ALBERT ALEXANDER STONIER) appears to have gamed the system, with fraudulent "likes" of this unremarkable solution submitted by 'sock-puppet' accounts. —DIV
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2 Comments
Willy Calvimontes
on 19 Jul 2016
i really don't get why it is wrong lol
tiju baby
on 18 Dec 2016
try again you are so best
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1 Comment
Hanna Wells
on 25 May 2016
This really saves time!
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4 Comments
Show
1 older comment
ENGSADI
on 21 May 2016
what about x = 1:10;
fyh1680
on 17 Sep 2016
im also wondering why ' x=1:10' doesn't work
Jana Rasras
on 18 Sep 2016
no,it works
try it without using ' ' (x = 1:10;)
Haitong Ye
on 31 Oct 2016
Nice!
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2 Comments
Heath McCabe
on 23 Mar 2016
I have tried multiple things that would create that vector, and it won't accept my answer. I am not sure what this question wants from me I guess.
Tim
on 24 Mar 2016
The output of your function is x, not x_correct, so remove "_correct" and it should work.
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1 Comment
Prajwal Kadambalithaya
on 3 Nov 2015
remove the square brackets,size will reduce even more
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1 Comment
Gabriel Gan
on 1 Oct 2015
why isnt the [] notation required for the solving of the puzzle?
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1 Comment
Gabriel Gan
on 1 Oct 2015
how do you improve on this solution?
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1 Comment
Shaleen
on 19 Aug 2015
Shorter than mine.
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1 Comment
Oli
on 23 Jul 2015
ermmm why not? It works when I type it in...
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3 Comments
Rehaan Abdulla
on 13 Jul 2015
Please help!!!!not sure where i went wrong
Elias Kurian
on 2 Aug 2015
You just need to type x=[1,2,3,4...10] or x=1:10
Just edit that line in the code. Not the whole thing
Tong Liu
on 30 Dec 2015
You should name the function exatly 'oneToTen',and apparently,your x is from 1 to 9,not 1 to 10.
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1 Comment
Francisco Salgado
on 26 Jun 2015
x=1:10 do the same.
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1 Comment
Wang Yunhe
on 16 Mar 2015
I do not deem that these problems can enhance one's performance.....
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1 Comment
Matthew Caron
on 7 Jan 2015
This question could have been a bit more challenging.
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2 Comments
Christopher Raabe
on 4 Jun 2014
why is this incorrect?
Tim
on 5 Jun 2014
You need to insert "function x=oneToTen" as the first line of your function.
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1 Comment
Ahsan Zamee
on 31 Dec 2013
give a value of y simple calling the function oneToTen. it will definitely work
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1 Comment
Kirk
on 17 Dec 2013
I do not understand the point of Cody... I cannot use "eval 1:10;" but I can use "str2num 1:10;" which is overhead + eval 1:10... Please make Cody evaluate the functions used in submitted code
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2 Comments
li
on 8 Jul 2013
what's the "str2num" mean?
Tim
on 8 Jul 2013
str2num means "convert string to number"; even more cryptic is the fact that "str2num 1:10" is equivalent to "str2num('1:10')" (Matlab allows you to omit the single quotes and parentheses when using functions that take character strings as arguments).
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2 Comments
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1 Comment
POORNAKUMAR
on 14 Mar 2013
please unlock the solution
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5 Comments
Show
2 older comments
John Kotrosa
on 19 Nov 2012
I’ve found that the huge strength of MATLAB is that it frees me to rapidly prototype numerical math problems – before I design a targeted solution. Such esoteric efficiencies as above are very clever and much credit goes to the person who presented it, however, this distracts rather than adds significant value to my use of MATLAB. Depending on the target machine (Desktop workstation or embedded device) I will ultimately use C/C++, assembly and VHDL to implement my process efficient code – never an interpreted language.
John Kotrosa
on 5 Dec 2012
This is an update since I had one person ask about my post...
I believe that speed is only one metric of performance, another is memory utilization. The key in this problem is the “type” of the variable stored internally. By using ans=1:10; the variable ans is (I believe) of the type double precision floating point (8 Bytes for each number). On the other hand by using str2num, a cast to an array of Characters (1 Byte each) is used to tightly store the tiny integer range of numbers needed. Thus the memory required to store ans is 8 times less.
SO, I’m not sure how they actually score (or weight) the importance between memory efficiency and execution time (and across multiple platforms and OS’s) since in your case you claim a faster execution time without the casting. This would need to be asked to a Mathworks person with specific insight to their code – sorry.
And back to my soapbox point… I’m using a machine that has 12 GB of RAM, so the difference between using 10 bytes or 80 bytes is not important to me.
HOWEVER, understanding this issue IS important so my hat is off to the Cody folks for the great (and fun) challenge!
Hope that helps!
john
Óscar
on 7 Dec 2012
The metric used to evaluate the performance of a solution is http://www.mathworks.com/matlabcentral/fileexchange/34754-calculate-size
As you can see if you inspect the code, it has nothing to do with speed or memory. That is why I proposed this solution, in order to show that you can become the leader with a code that is not efficient at all, either in execution speed or in memory use. Although I think the idea of Cody is great and challenging I believe that the metric that is used nowadays should be rethought.
HaveF
on 17 Dec 2012
interesting
Arist Kozhevnikov
on 14 Sep 2016
Cannot be reproduced, creates an error in execution in R2016a.
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1 Comment
John D'Errico
on 1 Feb 2012
cumsum(ones(1,10))
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