Problem 44500. Find the starting index of a consecutive condition

Given a logical vector v, and a positive integer n, return the smallest index i that satisfies:

all( v(i : i+n-1) ) == true

For Example,

v = logical([0, 1, 1, 0, 0, 1, 1, 1, 1, 1, 0]);
i = consecutiveFind(v, 4);


i = 6

If there is no sequence of n consecutive true, then i should be an empty array.

Solution Stats

51.09% Correct | 48.91% Incorrect
Last Solution submitted on Nov 01, 2023

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