Given two sides of a triangle, find the minimum and maximum possible area of the triangle.
the length of the third side has to be of integer-valued.
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Asif,
The results in the test suite seem to be based on the idea that the minimum and maximum areas are found by setting the third side to a3 = abs(a1-a2)+1 and a3=a1+a2-1, which is not correct. The correct maximum is somewhere in the middle. For example, in problem 2, the correct results are mn = 24.9987 and mx = 1250.0000.
yes.. i see that now.. my assumption was wrong.
Sorry for the misconception.
yet again we learn from our mistakes
Humm, I am certain that the minimum area of any triangle is zero, which corresponds to the degenerate case when one side is equal to the sum of the other two.