The instructions were a bit confusing at first. It would have been better to say "Find the row number of the outlying point."
Also, using the third row as an answer and a 3 in a column of zeros makes it seem like the intent was to provide unclear instructions. (Or they are just used to writing college textbooks ;) )
The test set cases 2,3 seems to have two outliers for each case. Please check it
Uses the formula for perpendicular distance of a point to a line when the line is not axis orthogonal.
Very interesting, why the test# 3 is not passed. It turned out that the two number
(x4-x1)*(y2-y1) is not the same as (y4-y1)*(x2-x1) due to floating point. I have to compare the subtraction with 10*eps.
Very interesting. I could not understand why I had not passed the test# 3. It turned out that the two number (x4-x1)*(y2-y1) and (y4-y1)*(x2-x1) are not the same due to floating point. My choice is to compare the absolute difference with 10*eps.
I'll try to improve it!
all tests are solved test3, i don't know what is the problem
I'm sorry for this :(
I got it on solution 600827.
http://www.mathworks.com/matlabcentral/cody/problems/661-spot-the-outlier/solutions/600827
great solution
Doesn't work with outlier in first position.
Could have been MUCH smaller, but corrcoef doesn't like x=0 the first test case.
4110 Solvers
Determine if a Given Number is a Triangle Number
322 Solvers
Increment a number, given its digits
562 Solvers
503 Solvers
Relative ratio of "1" in binary number
395 Solvers
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!