version 1.3.0.0 (7.58 KB) by
Zdravko Botev

fast and accurate state-of-the-art bivariate kernel density estimator

fast and accurate state-of-the-art bivariate kernel density estimator with diagonal bandwidth matrix.

The kernel is assumed to be Gaussian. The two bandwidth parameters are chosen optimally without ever

using/assuming a parametric model for the data or any "rules of thumb". Unlike many other procedures, this one

is immune to accuracy failures in the estimation of multimodal densities with widely separated modes (see examples).

INPUTS:

data - an N by 2 array with continuous data

n - size of the n by n grid over which the density is computed

n has to be a power of 2, otherwise n=2^ceil(log2(n)); the default value is 2^8;

MIN_XY,MAX_XY - limits of the bounding box over which the density is computed;

the format is:

MIN_XY=[lower_Xlim,lower_Ylim]

MAX_XY=[upper_Xlim,upper_Ylim].

The dafault limits are computed as:

MAX=max(data,[],1); MIN=min(data,[],1); Range=MAX-MIN;

MAX_XY=MAX+Range/4; MIN_XY=MIN-Range/4;

OUTPUT:

bandwidth - a row vector with the two optimal bandwidths for a bivaroate Gaussian kernel;

the format is:

bandwidth=[bandwidth_X, bandwidth_Y];

density - an 'n' by 'n' matrix containing the density values over the 'n' by 'n' grid;

density is not computed unless the function is asked for such an output;

X,Y - the meshgrid over which the variable "density" has been computed;

the intended usage is as follows:

surf(X,Y,density)

Example (simple Gaussian mixture)

clear all

% generate a Gaussian mixture with distant modes

data=[randn(500,2);

randn(500,1)+3.5, randn(500,1);];

% call the routine

[bandwidth,density,X,Y]=kde2d(data);

% plot the data and the density estimate

contour3(X,Y,density,50), hold on

plot(data(:,1),data(:,2),'r.','MarkerSize',5)

Example (Gaussian mixture with distant modes):

clear all

% generate a Gaussian mixture with distant modes

data=[randn(100,1), randn(100,1)/4;

randn(100,1)+18, randn(100,1);

randn(100,1)+15, randn(100,1)/2-18;];

% call the routine

[bandwidth,density,X,Y]=kde2d(data);

% plot the data and the density estimate

surf(X,Y,density,'LineStyle','none'), view([0,60])

colormap hot, hold on, alpha(.8)

set(gca, 'color', 'blue');

plot(data(:,1),data(:,2),'w.','MarkerSize',5)

Example (Sinusoidal density):

clear all

X=rand(1000,1); Y=sin(X*10*pi)+randn(size(X))/3; data=[X,Y];

% apply routine

[bandwidth,density,X,Y]=kde2d(data);

% plot the data and the density estimate

surf(X,Y,density,'LineStyle','none'), view([0,70])

colormap hot, hold on, alpha(.8)

set(gca, 'color', 'blue');

plot(data(:,1),data(:,2),'w.','MarkerSize',5)

Reference:

Kernel density estimation via diffusion

Z. I. Botev, J. F. Grotowski, and D. P. Kroese (2010)

Annals of Statistics, Volume 38, Number 5, pages 2916-2957

doi:10.1214/10-AOS799

Zdravko Botev (2020). kernel density estimation (https://www.mathworks.com/matlabcentral/fileexchange/17204-kernel-density-estimation), MATLAB Central File Exchange. Retrieved .

Created with
R2015a

Compatible with any release

**Inspired:**
synctest( X,varargin ), Cornerplot, Kernel Density Estimator for High Dimensions

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Emiliano RossoFethi Bencherkihow to detect how many peaks we have

saba gThank you for sharing the code. It is easy to generate the bivariate distribution. I have a question, is it possible to show the magnitude of density on contours?

Kai HeNiranjan KolhatkarI'm not able to find density probability of a point by this code. But in R language kde2d, we can find it by giving the point co-ordinates as the range input. Please give me any other approach to find the density probability for the point in a data set

aronne dell'ocaThank you so much! I used to compute a very challenging empirical copula density (i.e., for some quantiles the 2 variables are independent while they are perfectly correlated for others)! Results are very good in a reasonable time! Also at along the edges.

Thanks a lot

Bhawna MotwaniHello, this code is very useful -- thank you so much! Would it be possible for you to write a version that accepts weights corresponding to the data? That would be really really helpful. Thanks again.

Beata Orlecka-SikoraThank you for this solution. I wish to use your code in nonparametric hypothesis testing for the 3Dpdfs. I have a problem with random variable generation from the diffusion estimator. I use your Algorithm 3 on 2938 pp of the paper but the statistic which I use to compare 3D pdf (Bhattacharyya metric) provides evidences for large differences of pdfs, which should not appear I guess. I use at this moment Metropolis but it takes a lot of time for H testing. I would appreciate any suggestions on this matter.

suja devisir please send me background subtraction using kernel width estimationcoding

Guillem SoléCongratulations Zdravko for the code and the paper. I was just wondering if you happened to have a 3D version of the code.

Zanfir George SorinAslak GrinstedThank you. It would be great if you could add a parameter for EffectiveSampleSize being smaller than N. I want to use it to analyze the output of MCMC chains where the individual samples in data are not independent (using cornerplots). I've added the feature to my personal version.

Chris WilliamsSuper, thanks for thos

leo nidasThank you for sharing the code. Is there a way of obtaining the corresponding bivariate cdf as well as the marginal cdfs and the inverse marginal cdfs? Could you provide an example? Thank you.

PearlArpad RozsasAslak Grinstedyaq zhouI ran into the same error as described by Oliver，how can I fix it？

LeeFelipe UribeJakob NikolasIf you need to use a fixed bandwidth, just overwrite t_x and t_y in the main function. Thanks to Zdravko for this hint.

Jakob NikolasI ran into the same error as described by Oliver and fixed it by replacing

t_star=fzero( @(t)(t-evolve(t)),[0,0.1]);

with

options = optimset('FunValCheck','off')

try

t_star=fzero( @(t)(t-evolve(t)),[0,0.1],options);

catch

defaultError('override error, be cautious!');

t_star=0

end

OliverI am running the code perfectly on sets of 45 points (each has a X and Y coordinate). But when I try to only use a subset of those 45 points I get:

Error using fzero (line 274)

The function values at the interval endpoints must differ in sign.

Error in kde2d (line 101)

t_star=fzero(@(t)(t-evolve(t)),[0,0.1]);

Is code not able to handle the low sample size? Not sure what is happening. It seems to not be able to find a bandwidth.

sepidehAshaHi, I am using kde2d package for whale distribution data. I would like to plot the 50% and 95% kernels to look at where the core of the sightings are being made. Is this possible with this package? I am also not sure what the current legend means. I like the colour gradation that shows highly dense areas vs. lower density areas but it would be great if I could figure out why the numbers are as high as they are. I would appreciate any help on this matter please.

Thanks

Asha

Simonhey there

I have a problem: Im having a vector of log returns (1189 rows) whose distribution i want to estimate with a kernel distribution.

So i just type in: "ksdensity(returnvector)". I get a curve, which looks ok, but on the y axis, I get values up to 60 (nothing normalised). And the mean (by clicking on the curve, choosing tools and data statistics) is completely different from the normal mean calculated as "mean(returnvector)". I dont know what is wrong here, which mean do i need to chose and which std??

Thx

ArnaultA quick question about the bandwidth parameter. Does it have a unit? Does it correspond the the larger of the kernel related to the size of the grid cell?

Harish SSyedI keep getting negative probability densities, which is surprising as KDE is an addition of strictly positive numbers ...

TobiasHi,

I need to input an own bandwidth for the density estimation.

Is it possible to make changes to the code that allow either the input of another bandwidth or to change the data over which the density is computed after bandwidth estimation?

Thanks

Luca BaglivoRachelNo need to answer, I managed to do it by calculating the bin width from the [X, Y] (meshgrid) output.

RachelFirst of all, thank you for the code, it works great.

I want to get the marginal PDFs from the joint distribution, and am therefore doing:

[~,pdf_joint,X,Y]=kde2d(data);

m1 = sum(pdf_joint, 2); %marginal for signal 1 (column vector)

m2 = sum(pdf_joint, 1); %marginal for signal 2 (row vector)

How can I normalize m1 and m2 so that their total area is equal to unity?

Thank you.

JohnHi,

I just wanted to verify that the volume under the output curve is 1. Right?

Thanks

nameHi,

The 1d version of the kernel estimator also provides cdf values at the representative points. I would like to use these for 2d too. I don't have a strong background on this and I was not able to compute it.

Does anyone know how to compute cdf for 2d kernel?

El-ad David AmirAlexander StepanovHi. For the 1-dimensional estimation you've fixed the "fzero at 293:The function values at the interval endpoints must" error with a try-catch block using :

t_star=.28*N^(-2/5);

What is the correct expression for kde2d?

I'm guessing the power is (-1/3), but what is the coefficient (any where is it coming from)?

JERRYI am having the same problem as Gil Tidhar. When using the WAFO kde function, the minimum is 0 (which is what I expected), but your function returns negative values.

test code:

>> [temp, pab] = kde2d(rand(10000, 2),...

>> 2^4, [-3, -3], [5, 5]);

>> min(min(pab))

returns -0.0026

Arthur AllenI have exactly the same question as gwideman (21 Aug 2010) "Is it possible to use this procedure when the input data are weighted? " The 1-D ksdensity.m function has this ability. Thanks.

PauloI'm having the same problem reported above by Sue C (16 Feb 2010). A similar problem was found for the 1-d version of this code and, apparently, was only fixed there: http://www.mathworks.com/matlabcentral/fileexchange/14034-kernel-density-estimator

Alexander StepanovGreat code. One small improvements that I came across:

When data across one of the dimensions is constant, auto scaling is zero which leads to an error. Moreover, in that case it's better to increase/decrease max/min value, so that resulting meshgrid would not be 1-dimensional (which can cause wrong behavior in interpolation, for example)

Smth like this:

for ind=1:2

if MAX_XY(ind)==MIN_XY(ind)

MAX_XY(ind)=MAX_XY(ind)*1.1;

MIN_XY(ind)=MIN_XY(ind)/1.1;

end

end

Gil TidharThe minimum density values returned are NEGATIVE. This cannot be true for a density estimator and does not happen with other kernel type estimators that use positive definite Kernel functions.

NickMi MatthewMy god,you are so excellent.Thanks a lot!

gwidemanIs it possible to use this procedure when the input data are weighted? That is to say, input data have an X and Y value, and should not simply count as "1" at that location, but as some variable amount?

Thanks.

Anton HaugThe author of this subroutine contacted me and when I exchanged my code with him he pointed out where I had made an error and helped me to correct my code. His subroutine is not biased. The bias was createrd by my lack of understanding of how the subroutine worked. I thank the author for his help!!

Anton HaugI have tried this subroutine and found that it gives me a biased result. For samples from a mixture distribution of two Gaussians with known means, the kernel density is offset from the true mean in one dimension.

Sue CIt's easy to use .

but i got a problem;I am trying to do density estimation.

here is the m-file

%--------------(density estimation)------------------------------

clear all

data=[118,50;151,13;152,17;156,202;208,43;256,402;260,204;263,415;] ;

[bandwidth,density,X,Y]=kde2d(data);

contour3(X,Y,density,50), hold on

plot(data(:,1),data(:,2),'r.','MarkerSize',5)

%------------(density estimation)------------------------------(end)

and an error happened

??? Error using ==> fzero at 293

The function values at the interval endpoints must

differ in sign

Does anyone got the same error?

Davidi have the same question, and posted it on the other kernel estimator.

Dazhi JiangHi, Jiangguang,

I don't think the sum of the density values is necessary to be 1. In fact, the volume is.

By the way, even a single value of density function can be over than 1.

Thanks

JianguangI sum the 'density' and find sum(sum(denstiy)) > 1. This is an obivous bug and i don't know why. Should the density be normalizated to unit ?

MattShould this work when there are multiple points at one location?

If I input a vector or points, with s number of identical points, for example:

>> y=rand(400, 2); y(371:400, 1)=y(370,1); y(370:400,2)=y(370,1);

>> [bandwidth, density, X, Y]=kde2d(y);

I find that the minimum density value is negative, although the bandwidth is still real and positive.

Nikola ToljicJust what I needed.

Michael JordanNathanael YoderYing LinMaximum recursion limit of 500 reached. Use set(0,'RecursionLimit',N)

to change the limit.

Alexander Sepúlvedajagabandhu paulgood.

AMin GheibiIt's easy to use and good organized code. I suggest it.

dan pThis is some really nice code. It runs very quickly and is easy to get up and running. The author also provides plenty of comments and examples.

Thomas T.Easy to use bivariate kernel density estimation procedure. Thanks for sharing the code.