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version (549 Bytes) by Richard Heitz
Returns indices of n consecutive numbers (you specify the number you want)

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Updated 13 Feb 2009

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Accepts: a vector of numbers

Returns: the indices of n consecutive numbers of your specification

For instance, if you want to find the first instance of 10 consecutive 1's in a vector,

x = findRuns(vector,10,1)

Code may not be pretty, but it works and is quite fast.

Cite As

Richard Heitz (2020). findRuns.m (, MATLAB Central File Exchange. Retrieved .

Comments and Ratings (2)

Richard Heitz

I agree, using strfind is a much more simplistic method. However, it fails to find ALL instances meeting a criterion. For instance, givin the vector [0 1 1 1 1 0 0], say you want to find instances of 3 or more 1's in a row.
Using strfind you'll get back [2 3]. Using findRuns, you'll get [2 3 4 5].

Jos (10584)

Before evaluating the algorithm, you can improve the help section and add comments to the code. A proper help section consists of (1) an H1 line, (2) and explanation of the algorithm in plain language with a description of the input and output parameters, (3) and example, and perhaps (4) a See Also line.

As it is, "help finruns" returns nothing really useful, unless one take a closer look at the code.

The approach itself is also the result of translating pseudocode (C?) directly into matlab. Using a logical vector, combined with strfind easily returns the indices: Q = vector == value ; startidx = strfind(Q,[ 0 1]) ; etc ... which has been described many times on the newsgroup.

MATLAB Release Compatibility
Created with R2008b
Compatible with any release
Platform Compatibility
Windows macOS Linux

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