This code defines an existing function and step size which you can change as per requirement.
P.S: This code has no new feature compared to existing codes available online. Intention behind posting this very simple code is to help students understand the concept and solve assignments.
Judah S (2021). Runge Kutta 4th order ode (https://www.mathworks.com/matlabcentral/fileexchange/29851-runge-kutta-4th-order-ode), MATLAB Central File Exchange. Retrieved .
Why does it not work for initial conditions y(0) = some number?
It does not work for y(0) = 0 initial condition
Great work! What about a code for Runge Kutta method for second order ODE. Something of this nature:
d^2y/dx^2 + 0.6*dy/dx 0.8y = 0
how can i solve SIR model using RK4 method in matlab? can you write the code please
sir can you assist me ,that how we can apply 4th order Runge kutta method for 4 coupled equation?
dx/dt=−ax − eω + yz
dy/dt= by + xz
dz/dt= cz + fω − xy
dω/dt = dω – gz
a = 50, b =−16, c = 10, d = 0.2, e = 10, f = 16, g = 0.5
Step size 0.001 .
@Shahzaib Asif Very helpful program.JazakAllah
How do I run/call to this code?
for this function : f'''' - f*f''' + 4*g = 0
where i need to insert it in this code?
% Runge Kutta Method 4th Order
% function @(x,y) e.g. f=@(x,y)(x+y);
% a = the point up to which you obtain the results
% x0 = initial condition of x
% y0 = initial condition of y
% step size
x = x0:h:a;
y(1) = y0;
k1 = f(x(i),y(i));
k2 = f(x(i)+0.5*h,y(i)+0.5*h*k1);
k3 = f((x(i)+0.5*h),(y(i)+0.5*h*k2));
k4 = f((x(i)+h),(y(i)+k3*h));
y(i+1) = y(i) + (1/6)*(k1+2*k2+2*k3+k4)*h;
%Shahzaib Asif (zaibi7402)
Very good to learn. Thanks.
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