I need to create a program that calculates square root of 2 using loop. starting with t=0.5. I need to stop cycle (and print iteration number i) when the t(i) is same for approximation : if abs((t(i)-t(i+1)))<10^-6. Can anyone help me? please please please :)
t(1)=0.5
for i=1:10
t(i+1)=1/2*(t(i)+2/t(i));
if abs((t(i)-t(i+1)))<10^-6
[ i, t(i)]
else
end
end